Edexcel GCSE Maths · 1MA1

June 2018 Paper 1 Foundation

Non-calculator · 26 questions · 80 marks · 1 hour 30 minutes. Try each question on paper, then press "Show answer".

Question 1

Rounding and estimation1 markGrade 1No calculator
Round a four-digit whole number to the nearest thousand.

© Pearson Education Ltd. June 2018 Paper 1 (Foundation, non-calculator), question 1.

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Answer600060001 mark

Worked solution Checked against the mark scheme

Look at the hundreds digit of 6324: it is 3, which is less than 5.

So round down to 6000.

Watch out: Rounding up to 7000 or giving 6300.

Question 2

Put a set of positive and negative integers, then a set of decimals, in ascending order.

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(a)−6,−5,0,6,12-6, -5, 0, 6, 121 mark
(b)0.078,0.708,0.78,0.870.078, 0.708, 0.78, 0.871 mark

Worked solution Checked against the mark scheme

(a) Negatives come first, and −6-6 is smaller than −5-5: −6,−5,0,6,12-6, -5, 0, 6, 12

(b) Write each with three decimal places: 0.078, 0.780, 0.870, 0.708.

Order: 0.078,0.708,0.78,0.870.078, 0.708, 0.78, 0.87

Watch out: Thinking −5-5 is smaller than −6-6.

Question 3

Percentages1 markGrade 1No calculator
Convert a percentage into a fraction.

© Pearson Education Ltd. June 2018 Paper 1 (Foundation, non-calculator), question 3.

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Answer20100\frac{20}{100} or 15\frac{1}{5}1 mark

Worked solution Checked against the mark scheme

Per cent means out of 100, so 20%=2010020\% = \frac{20}{100}.

This simplifies to 15\frac{1}{5}.

Watch out: Writing 20/10 or 1/20.

Question 4

Fractions1 markGrade 1No calculator
Pick out the one fraction in a list that is not equal to one quarter.

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Answer39\frac{3}{9}1 mark

Worked solution Checked against the mark scheme

Simplify each: 416=14\frac{4}{16} = \frac{1}{4}, 28=14\frac{2}{8} = \frac{1}{4}, 1560=14\frac{15}{60} = \frac{1}{4}, but 39=13\frac{3}{9} = \frac{1}{3}.

So the odd one out is 39\frac{3}{9}.

Question 5

Factors, multiples and primes1 markGrade 1No calculator
Find the smallest multiple of 7 that is even.

© Pearson Education Ltd. June 2018 Paper 1 (Foundation, non-calculator), question 5.

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Answer14141 mark

Worked solution Checked against the mark scheme

Multiples of 7: 7, 14, 21, ...

7 is odd, so the first even one is 14.

Watch out: Giving 7, which is odd.

Question 6

Expanding brackets and simplifying2 marksGrade 1No calculator
Simplify a product of a number and an algebraic term, then collect like terms.

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(a)12t12t1 mark
(b)7a7a1 mark

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(a) 3×4t=12t3 \times 4t = 12t

(b) 8a−3a=5a8a - 3a = 5a, then 5a+2a=7a5a + 2a = 7a

Watch out: In (b), working out 3a+2a3a + 2a first and getting 3a3a.

Question 7

Probability scale and basic probability5 marksGrade 2No calculator
Read events off a probability scale, then show that the chance of picking one of two colours of counter is two thirds.

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(a)D1 mark
(b)B1 mark
(c)Green =6= 6, so P=2+612=812=23P = \frac{2+6}{12} = \frac{8}{12} = \frac{2}{3}3 marks

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(a) Certain means probability 1, which is D.

(b) Unlikely means between 0 and a half, which is B.

(c) Green =12−(3+1+2)=6= 12 - (3 + 1 + 2) = 6

Yellow or green =2+6=8= 2 + 6 = 8 counters

P=812=23P = \frac{8}{12} = \frac{2}{3}

Watch out: Forgetting the blue counter when working out the number of green ones.

Question 8

Direct and inverse proportion2 marksGrade 2No calculator
Find the cost of a smaller amount of meat given the price of a larger amount.

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Answer£36£362 marks

Worked solution Checked against the mark scheme

1 kg costs 54÷3=£1854 \div 3 = £18

2 kg cost 2×18=£362 \times 18 = £36

Watch out: Working out 54÷2=2754 \div 2 = 27.

Question 9

Circles: parts, circumference and area2 marksGrade 2No calculator
Name two straight lines drawn on a circle.

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(a)Radius1 mark
(b)Tangent1 mark

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(a) A line from the centre to the edge is a radius.

(b) A line that touches the circle at just one point is a tangent.

Watch out: Calling the radius a diameter.

Question 10

Split the total cost of a holiday equally between four people.

© Pearson Education Ltd. June 2018 Paper 1 (Foundation, non-calculator), question 10.

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Answer£535£5353 marks

Worked solution Checked against the mark scheme

Total =1280+640+220=£2140= 1280 + 640 + 220 = £2140

Each share =2140÷4=£535= 2140 \div 4 = £535

Watch out: Adding the costs but not dividing by 4 (or dividing only the plane tickets).

Question 11

Factors, multiples and primes2 marksGrade 3No calculator
Give counter-examples to two false statements about factors and odd numbers.

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(a)e.g. 3 is a factor of 121 mark
(b)e.g. 231 mark

Worked solution Checked against the mark scheme

(a) 12 is even, but 3×4=123 \times 4 = 12, so 3 is an odd factor of 12.

(b) 23 is odd, but its digit 2 is even.

Watch out: Giving an example that agrees with the statement instead of one that breaks it.

Question 12

Charts, graphs and time series7 marksGrade 3No calculator
Read a composite bar chart of computer sales, total one category, identify the fastest-growing item and comment on a claim about profit.

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(a)1001001 mark
(b)6606603 marks
(c)Tablets: they rose from 60 to 340, an increase of 2802 marks
(d)No: the chart gives numbers sold, not prices or profit1 mark

Worked solution Checked against the mark scheme

(a) The desktop section in 2015 reaches 100.

(b) Laptops: 260−100=160260 - 100 = 160, 340−120=220340 - 120 = 220, 440−160=280440 - 160 = 280

Total =160+220+280=660= 160 + 220 + 280 = 660

(c) Tablets: 320−260=60320 - 260 = 60 in 2015 up to 780−440=340780 - 440 = 340 in 2017, a rise of 280. Tablets grew most.

(d) No: we know how many were sold, not the profit on each item.

Watch out: Reading the top of the laptop section (260) as the number of laptops instead of subtracting the desktop part.

Question 13

Cut two lengths off a piece of wire and find how many equal shorter pieces can be cut from what is left.

© Pearson Education Ltd. June 2018 Paper 1 (Foundation, non-calculator), question 13.

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Answer333 marks

Worked solution Checked against the mark scheme

Left after two pieces: 240−2×45=150240 - 2 \times 45 = 150 cm

150÷40=3.75150 \div 40 = 3.75

Only whole pieces count, so 3.

Watch out: Rounding 3.75 up to 4.

Question 14

Percentages4 marksGrade 4No calculator
Compare savings given as a percentage, a fraction spent and a ratio, to see who saves most.

© Pearson Education Ltd. June 2018 Paper 1 (Foundation, non-calculator), question 14.

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AnswerIsabel (saves 30%, against 28% and 25%)4 marks

Worked solution Checked against the mark scheme

Gavin saves 28%.

Harry spends 34\frac{3}{4}, so saves 14=25%\frac{1}{4} = 25\%.

Isabel saves 33+7=310=30%\frac{3}{3+7} = \frac{3}{10} = 30\%.

30% is the biggest, so Isabel saves the most.

Watch out: Taking Isabel's share as 3/7 instead of 3/10.

Question 15

Percentages2 marksGrade 3No calculator
Find a percentage of a mass without a calculator.

© Pearson Education Ltd. June 2018 Paper 1 (Foundation, non-calculator), question 15.

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Answer2424 grams2 marks

Worked solution Checked against the mark scheme

10% of 160 =16= 16

5% =16÷2=8= 16 \div 2 = 8

15% =16+8=24= 16 + 8 = 24 g

Watch out: Finding 15% then subtracting it from 160 (giving 136).

Question 16

Substitute values into a formula, expand a single bracket and solve a linear equation with brackets.

© Pearson Education Ltd. June 2018 Paper 1 (Foundation, non-calculator), question 16.

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(a)14142 marks
(b)4e2+8e4e^2 + 8e2 marks
(c)m=11m = 112 marks

Worked solution Checked against the mark scheme

(a) P=4×5+3×(−2)=20−6=14P = 4 \times 5 + 3 \times (-2) = 20 - 6 = 14

(b) 4e×e=4e24e \times e = 4e^2 and 4e×2=8e4e \times 2 = 8e, so 4e2+8e4e^2 + 8e

(c) Divide by 3: m−4=7m - 4 = 7, so m=11m = 11

Watch out: In (a), treating 3×−23 \times -2 as +6+6 to get 26.

Question 17

Ratio2 marksGrade 4No calculator
Turn a fraction of a box of chocolates into a ratio in the form 1 : n.

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Answer1:31 : 32 marks

Worked solution Checked against the mark scheme

Nuts: 14\frac{1}{4}, no nuts: 1−14=341 - \frac{1}{4} = \frac{3}{4}

Ratio 14:34=1:3\frac{1}{4} : \frac{3}{4} = 1 : 3

Watch out: Writing 1 : 4 (part to whole instead of part to part).

Question 18

Venn diagrams and sets3 marksGrade 4No calculator
List the union of two sets of numbers and describe their intersection.

© Pearson Education Ltd. June 2018 Paper 1 (Foundation, non-calculator), question 18.

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(a)15,17,19,20,21,23,2515, 17, 19, 20, 21, 23, 252 marks
(b)Odd multiples of 5 (15 and 25)1 mark

Worked solution Checked against the mark scheme

A={15,20,25}A = \{15, 20, 25\}, B={15,17,19,21,23,25}B = \{15, 17, 19, 21, 23, 25\}

(a) Union is everything in either: 15, 17, 19, 20, 21, 23, 25

(b) Intersection is in both: 15 and 25, the odd multiples of 5.

Watch out: Mixing up union and intersection.

Question 19

Fractions4 marksGrade 4No calculatorOn both tiers
Add two mixed numbers and divide a mixed number by a fraction.

© Pearson Education Ltd. June 2018 Paper 1 (Foundation, non-calculator), question 19.

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(a)311283\frac{11}{28}2 marks
(b)1351\frac{3}{5}2 marks

Worked solution Checked against the mark scheme

(a) Whole numbers: 2+1=32 + 1 = 3. Fractions: 17+14=428+728=1128\frac{1}{7} + \frac{1}{4} = \frac{4}{28} + \frac{7}{28} = \frac{11}{28}

Answer 311283\frac{11}{28}

(b) 115=651\frac{1}{5} = \frac{6}{5}, then 65×43=2415=85=135\frac{6}{5} \times \frac{4}{3} = \frac{24}{15} = \frac{8}{5} = 1\frac{3}{5}

Watch out: In (b), dividing without flipping the second fraction.

Question 20

Ratio3 marksGrade 5No calculator
Use two linked ratios and a known number of bungalows to find the number of houses.

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Answer1401403 marks

Worked solution Checked against the mark scheme

Flats : bungalows =8:5= 8 : 5, and 50÷5=1050 \div 5 = 10, so flats =8×10=80= 8 \times 10 = 80

Houses : flats =7:4= 7 : 4, and 80÷4=2080 \div 4 = 20, so houses =7×20=140= 7 \times 20 = 140

Watch out: Using the 4 in the first ratio as if it matched the 8 in the second.

Question 21

Work out the percentage profit when sweets are bought in bulk and sold in bags.

© Pearson Education Ltd. June 2018 Paper 1 (Foundation, non-calculator), question 21.

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Answer30%30\%4 marks

Worked solution Checked against the mark scheme

5 kg =5000= 5000 g, so 5000÷250=205000 \div 250 = 20 bags

Takings =20×65p=£13= 20 \times 65\text{p} = £13

Profit =13−10=£3= 13 - 10 = £3

Percentage profit =310×100=30%= \frac{3}{10} \times 100 = 30\%

Watch out: Giving 130% (takings as a percentage of cost).

Question 22

Rounding and estimation4 marksGrade 4No calculator
Estimate the number of days to finish a long cycle race using rounded values, then say how a faster speed changes the answer.

© Pearson Education Ltd. June 2018 Paper 1 (Foundation, non-calculator), question 22.

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(a)about 25 days (e.g. 3000÷15÷83000 \div 15 \div 8); any answer that follows correctly from sensible rounding3 marks
(b)Fewer days would be needed (or no change if 16.27 still rounds to 15)1 mark

Worked solution Checked against the mark scheme

(a) Round: 30003000 miles, 1515 mph

Hours =3000÷15=200= 3000 \div 15 = 200

Days =200÷8=25= 200 \div 8 = 25

(b) A higher speed means fewer hours, so he would need fewer days.

Watch out: Not rounding, and trying to divide by 15.12 exactly.

Question 23

Volume and surface area6 marksGrade 5No calculator
Draw the front elevation of a square-based pyramid and find its total surface area.

© Pearson Education Ltd. June 2018 Paper 1 (Foundation, non-calculator), question 23.

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(a)Isosceles triangle, base 6 cm, height 4 cm2 marks
(b)96 cm296\text{ cm}^24 marks

Worked solution Checked against the mark scheme

(a) From the front you see a triangle: base 6 cm, height 4 cm, apex above the middle of the base.

(b) Each sloping face: 12×6×5=15 cm2\frac{1}{2} \times 6 \times 5 = 15\text{ cm}^2

Four faces: 4×15=604 \times 15 = 60. Base: 6×6=366 \times 6 = 36

Total =60+36=96 cm2= 60 + 36 = 96\text{ cm}^2

Watch out: Using the vertical height 4 cm instead of the slant height 5 cm for the triangles (giving 84).

Question 24

Coordinates and straight-line graphs5 marksGrade 5No calculator
Use the coordinates of two corners of a stepped pattern of four equal squares to find another marked point.

© Pearson Education Ltd. June 2018 Paper 1 (Foundation, non-calculator), question 24.

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Answer(22,20)(22, 20)5 marks

Worked solution Checked against the mark scheme

Width =38−6=32= 38 - 6 = 32, covering four square widths, so each side is 32÷4=832 \div 4 = 8.

C is two sides right of A: x=6+2×8=22x = 6 + 2 \times 8 = 22

C is two sides below B: y=36−2×8=20y = 36 - 2 \times 8 = 20

So C=(22,20)C = (22, 20)

Watch out: Assuming the height 29 is also four sides, because the squares overlap vertically.

Question 25

Coordinates and straight-line graphs3 marksGrade 4No calculator
Draw the graph of a straight line with negative gradient over a given range of x.

© Pearson Education Ltd. June 2018 Paper 1 (Foundation, non-calculator), question 25.

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AnswerStraight line from (−3,13)(-3, 13) to (3,−11)(3, -11)3 marks

Worked solution Checked against the mark scheme

Make a table with y=1−4xy = 1 - 4x:

xx: −3, −2, −1, 0, 1, 2, 3

yy: 13, 9, 5, 1, −3, −7, −11

Plot the points and join them with a ruler.

Watch out: Working out 1−4×(−3)1 - 4 \times (-3) as −11-11 instead of 13.

Question 26

Vectors2 marksGrade 4No calculator
Combine two column vectors using a scalar multiple and addition.

© Pearson Education Ltd. June 2018 Paper 1 (Foundation, non-calculator), question 26.

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Answer(911)\begin{pmatrix} 9 \\ 11 \end{pmatrix}2 marks

Worked solution Checked against the mark scheme

2a=(104)2\mathbf{a} = \begin{pmatrix} 10 \\ 4 \end{pmatrix}

2a+b=(10+(−1)4+7)=(911)2\mathbf{a} + \mathbf{b} = \begin{pmatrix} 10 + (-1) \\ 4 + 7 \end{pmatrix} = \begin{pmatrix} 9 \\ 11 \end{pmatrix}

Watch out: Doubling b as well as a.

Finished the paper?

Add up your marks for all three papers and see what grade that would have been.