Ratio, proportion and rates of change

Percentage change and reverse percentages

33 past-paper questions, easiest first. Try each one, then reveal the answer.

Foundation & Higher23 of 33 from Foundation papers

Revision guide by The Full Marks

Percentage change and reverse percentages: what you need to know

Percentage change covers increases, decreases, profit and loss, simple interest and working back to an original amount. Multipliers make all of these quicker and more reliable.

Key facts

  • Increase by x%x\%: multiply by 1+x1001 + \frac{x}{100} (e.g. +20%→×1.2+20\% \to \times 1.2).
  • Decrease by x%x\%: multiply by 1−x1001 - \frac{x}{100} (e.g. −15%→×0.85-15\% \to \times 0.85, −3%→×0.97-3\% \to \times 0.97, not 0.70.7).
  • Percentage change =changeoriginal×100= \dfrac{\text{change}}{\text{original}} \times 100. For profit or loss, the original is the cost price.
  • Original value == new value ÷\div multiplier.
  • Simple interest is the same amount each year: interest == amount ×\times rate ×\times years. Add it on if you need the total in the account; to find the yearly rate, divide the total interest by the number of years first.

Increase or decrease by a percentage

  1. Write the multiplier.
  2. Multiply the original amount by it.

Reverse percentage (finding the original)

  1. Write the multiplier that was used.
  2. Divide the new amount by the multiplier. Don't take a percentage of the new amount.

Worked examples

Example 1 Foundation · grade 4

(a) A TV costing £450 is reduced by 15%15\%. Find the sale price. (b) Jamal buys a bike for £40 and sells it for £52. Find his percentage profit.

Show the solution

(a) Multiplier =1−0.15=0.85= 1 - 0.15 = 0.85
450×0.85=£382.50450 \times 0.85 = £382.50
(b) Profit =52−40=£12= 52 - 40 = £12
1240×100=30%\frac{12}{40} \times 100 = 30\% profit

Example 2 Foundation · grade 5

After a 20%20\% price rise, a concert ticket costs £54. What was the price before the rise?

Show the solution

New price =120%= 120\% of the original, multiplier 1.21.2
Original =54÷1.2=£45= 54 \div 1.2 = £45
Check: 45×1.2=5445 \times 1.2 = 54

Common mistakes

  • Reverse percentages: taking 20% off £54 gives £43.20, which is wrong. Divide by 1.2.
  • Dividing the change by the new value (or by the selling price, for profit) instead of the original value or cost price.
  • Adding successive changes: +10%+10\% then +10%+10\% is ×1.21\times 1.21, not +20%+20\%.
  • Simple interest: using compound interest, or giving the final amount when the question asks for the interest (or the other way round).

Exam tips

  • Write money answers with 2 decimal places, e.g. £382.50 rather than £382.5.
  • Check a reverse percentage by applying the change to your answer.

Questions people ask

How do you calculate percentage increase?

Find the increase, divide by the original amount and multiply by 100.

How do you find the original price before a discount?

Divide the sale price by the multiplier. After 25% off, divide by 0.75.

What is simple interest?

Interest worked out on the original amount only, so you earn the same each year. £2000 at 3% for 4 years earns 2000×0.03×4=£2402000 \times 0.03 \times 4 = £240.

Exam questions: Percentage change and reverse percentages (33, easiest first)

Percentage change and reverse percentages3 marksGrade 3No calculatorFoundation
June 2022 · Paper 1 Foundation · Q19
Increase an amount by a percentage without a calculator.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 19.

Show answer
Answer2883 marks

Worked solution Checked against the mark scheme

10%10\% of 240 is 24, so 20%20\% is 4848

240+48=288240 + 48 = 288

Watch out: Giving just 48, the increase, as the answer.

Percentage change and reverse percentages5 marksGrade 3No calculatorFoundation
November 2020 · Paper 1 Foundation · Q17
Apply a fractional reduction and then a percentage reduction to a price and compare with a budget.

© Pearson Education Ltd. November 2020 Paper 1 (Foundation, non-calculator), question 17.

Show answer
AnswerYes: the Tuesday price is £3605 marks

Worked solution Checked against the mark scheme

Monday: 110\frac{1}{10} of £500 is £50, so the price is 500−50=£450500 - 50 = £450.

Tuesday: 20% of £450 is 0.2×450=£900.2 \times 450 = £90, so the price is 450−90=£360450 - 90 = £360.

£360 is less than £400, so yes, Chris can buy it.

Watch out: Taking 20% off the original £500 instead of off the Monday sale price.

Percentage change and reverse percentages3 marksGrade 3CalculatorFoundation
Specimen · Paper 2 Foundation · Q11
Apply a percentage reduction then a further cash reduction and decide if £40 is enough.

© Pearson Education Ltd. Specimen Paper 2 (Foundation, calculator), question 11.

Show answer
AnswerNo: the week 2 price is £423 marks

Worked solution Checked against the mark scheme

Week 1: 65×0.8=£5265 \times 0.8 = £52

Week 2: 52−10=£4252 - 10 = £42

£42 is more than £40, so Maria does not have enough.

Watch out: Taking 20% and £10 off together from £65 as 30%.

Percentage change and reverse percentages1 markGrade 4No calculatorHigher
June 2024 · Paper 1 Higher · Q9
Find the percentage reduction when a sale price is 0.7 of the normal price.

© Pearson Education Ltd. June 2024 Paper 1 (Higher, non-calculator), question 9.

Show answer
AnswerR=30R = 301 mark

Worked solution Checked against the mark scheme

A multiplier of 0.7 means the sale price is 70% of the normal price.

The reduction is 100%−70%=30%100\% - 70\% = 30\%, so R=30R = 30

Watch out: Giving R=70R = 70, the percentage paid rather than the reduction.

Percentage change and reverse percentages6 marksGrade 4CalculatorFoundation
November 2024 · Paper 2 Foundation · Q17
Apply a percentage decrease to a price and work back from a bonus percentage to a sales total.

© Pearson Education Ltd. November 2024 Paper 2 (Foundation, calculator), question 17.

Show answer
(a)£265.053 marks
(b)£80003 marks

Worked solution Checked against the mark scheme

(a) 285×0.93=£265.05285 \times 0.93 = £265.05

(b) The bonus is 2100−1700=£4002100 - 1700 = £400.

5%=4005\% = 400, so 1%=801\% = 80 and 100%=80×100=£8000100\% = 80 \times 100 = £8000.

Watch out: In (b), finding 5% of 2100 instead of treating £400 as the 5%.

Percentage change and reverse percentages2 marksGrade 4No calculatorOn both tiers
June 2023 · Paper 1 Foundation · Q26
Work backwards from the amount a percentage increase adds to find the original price.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 26.

Show answer
Answer£12002 marks

Worked solution Checked against the mark scheme

20% of the price is £240.

10% is £120, so 100% is 120×10=£1200120 \times 10 = £1200

Watch out: Adding 20% to 240 or finding 20% of 240.

Percentage change and reverse percentages5 marksGrade 4CalculatorFoundation
June 2022 · Paper 2 Foundation · Q19
Find the lowest price per bag of sweets that gives at least a 35% profit on the box.

© Pearson Education Ltd. June 2022 Paper 2 (Foundation, calculator), question 19.

Show answer
Answer£1.195 marks

Worked solution Checked against the mark scheme

Number of bags: 3000÷150=203000 \div 150 = 20

Total needed with 35% profit: 17.60×1.35=23.7617.60 \times 1.35 = 23.76

Price per bag: 23.76÷20=1.18823.76 \div 20 = 1.188

Round up so the profit is at least 35%: £1.19

Watch out: Rounding 1.188 down to 1.18, or forgetting to convert kg to g.

Percentage change and reverse percentages4 marksGrade 4CalculatorOn both tiers
June 2022 · Paper 3 Foundation · Q25
Compare the cost of 15 rolls of wallpaper from two shops with different offers.

© Pearson Education Ltd. June 2022 Paper 3 (Foundation, calculator), question 25.

Show answer
AnswerChic Decor (£180 compared with £184.80)4 marks

Worked solution Checked against the mark scheme

Chic Decor: 15÷3=515 \div 3 = 5 lots of £36, so 5×36=£1805 \times 36 = £180

Style Papers: 3×70=£2103 \times 70 = £210, then 210×0.88=£184.80210 \times 0.88 = £184.80

£180 < £184.80, so buy from Chic Decor.

Watch out: Taking 12% off only one pack, or finding 12% but not subtracting it.

Percentage change and reverse percentages3 marksGrade 4No calculatorFoundation
November 2021 · Paper 1 Foundation · Q19
Find the percentage loss when an item is sold for less than it cost.

© Pearson Education Ltd. November 2021 Paper 1 (Foundation, non-calculator), question 19.

Show answer
Answer3030%3 marks

Worked solution Checked against the mark scheme

Loss: £80−£56=£24£80 - £56 = £24

Percentage loss: 2480×100=30%\frac{24}{80} \times 100 = 30\%

Watch out: Dividing by 56 instead of the original price, 80.

Percentage change and reverse percentages4 marksGrade 4No calculatorOn both tiers
November 2021 · Paper 1 Foundation · Q23
Apply a percentage decrease and a percentage increase to two house values and compare them.

© Pearson Education Ltd. November 2021 Paper 1 (Foundation, non-calculator), question 23.

Show answer
AnswerRahim's: £208 000 compared with Tamara's £176 0004 marks

Worked solution Checked against the mark scheme

Tamara: 220 000×0.8=£176 000220\,000 \times 0.8 = £176\,000

Rahim: 160 000×1.3=£208 000160\,000 \times 1.3 = £208\,000

208 000>176 000208\,000 > 176\,000, so Rahim's house has the greater value.

Watch out: Finding only the change (44 000 and 48 000) and comparing those.

Percentage change and reverse percentages4 marksGrade 4CalculatorFoundation
November 2019 · Paper 2 Foundation · Q20
Substitute into a formula for a building's height and show the error is under 5% of the real height.

© Pearson Education Ltd. November 2019 Paper 2 (Foundation, calculator), question 20.

Show answer
AnswerEstimate 452 m, difference 10 m, which is about 2.26% (under 5%)4 marks

Worked solution Checked against the mark scheme

Estimate: H=4×110+12=452H = 4 \times 110 + 12 = 452 m

Difference: 452−442=10452 - 442 = 10 m

5%5\% of 442 =22.1= 22.1 m

10<22.110 < 22.1, so the difference is less than 5% of the real height (10442×100=2.26%\frac{10}{442} \times 100 = 2.26\%).

Watch out: Finding 5% of the estimate (452) instead of the real height.

Percentage change and reverse percentages3 marksGrade 4CalculatorFoundation
November 2019 · Paper 3 Foundation · Q21
Work out the percentage profit made on selling a house.

© Pearson Education Ltd. November 2019 Paper 3 (Foundation, calculator), question 21.

Show answer
Answer8%3 marks

Worked solution Checked against the mark scheme

Profit: 158 220−146 500=11 720158\,220 - 146\,500 = 11\,720

Percentage profit =11 720146 500×100=8%= \frac{11\,720}{146\,500} \times 100 = 8\%

Watch out: Dividing by the selling price instead of the buying price.

Percentage change and reverse percentages4 marksGrade 4No calculatorHigher
June 2018 · Paper 1 Higher · Q3
Find the percentage profit made by buying sweets in bulk and selling them in small bags.

© Pearson Education Ltd. June 2018 Paper 1 (Higher, non-calculator), question 3.

Show answer
Answer30%4 marks

Worked solution Checked against the mark scheme

5 kg=5000 g5\text{ kg} = 5000\text{ g}, so there are 5000÷250=205000 \div 250 = 20 bags.

Takings: 20×£0.65=£1320 \times £0.65 = £13

Profit =£13−£10=£3= £13 - £10 = £3

Percentage profit =310×100=30%= \frac{3}{10} \times 100 = 30\%

Watch out: Giving 130%, the takings as a percentage of the cost, rather than the profit.

Percentage change and reverse percentages2 marksGrade 4CalculatorFoundation
November 2018 · Paper 2 Foundation · Q18
Explain an error in a percentage increase multiplier and give the multiplier for a percentage decrease.

© Pearson Education Ltd. November 2018 Paper 2 (Foundation, calculator), question 18.

Show answer
(a)1.3 is a 30% increase; for 3% he needs 1.031 mark
(b)150×0.97=145.5150 \times 0.97 = 145.51 mark

Worked solution Checked against the mark scheme

(a) 1.3=130%1.3 = 130\%, which adds 30%. A 3% increase uses 1.031.03: 150×1.03=154.5150 \times 1.03 = 154.5.

(b) Decrease by 3%: 100%−3%=97%=0.97100\% - 3\% = 97\% = 0.97

150×0.97=145.5150 \times 0.97 = 145.5

Watch out: Using 0.7 for a 3% decrease.

Percentage change and reverse percentages3 marksGrade 4CalculatorOn both tiers
November 2018 · Paper 3 Foundation · Q21
Work out a percentage increase between two yearly costs.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 21.

Show answer
Answer260.4%260.4\%3 marks

Worked solution Checked against the mark scheme

Increase: 883−245=638883 - 245 = 638

Percentage increase: 638245×100=260.4%\frac{638}{245} \times 100 = 260.4\%

Watch out: Dividing by the new price (883) instead of the original.

Percentage change and reverse percentages4 marksGrade 5CalculatorOn both tiers
November 2024 · Paper 2 Foundation · Q25
Compare two percentage increases to test a claim.

© Pearson Education Ltd. November 2024 Paper 2 (Foundation, calculator), question 25.

Show answer
AnswerYes: 11.8%11.8\% is more than 7×1.54%=10.8%7 \times 1.54\% = 10.8\%4 marks

Worked solution Checked against the mark scheme

First class: 85−7676×100=11.84%\frac{85 - 76}{76} \times 100 = 11.84\%

Second class: 66−6565×100=1.54%\frac{66 - 65}{65} \times 100 = 1.54\%

7×1.54=10.77%7 \times 1.54 = 10.77\%, and 11.84>10.7711.84 > 10.77, so Filip is correct.

Watch out: Comparing the actual increases (9p and 1p) instead of percentages.

Percentage change and reverse percentages5 marksGrade 5CalculatorOn both tiers
November 2024 · Paper 3 Foundation · Q21
Share a total in a ratio and use buying and selling prices to find the percentage profit.

© Pearson Education Ltd. November 2024 Paper 3 (Foundation, calculator), question 21.

Show answer
Answer45.6%45.6\%5 marks

Worked solution Checked against the mark scheme

One part: 240÷8=30240 \div 8 = 30, so 90 pens and 150 pencils.

Cost: 90×9+150×6=171090 \times 9 + 150 \times 6 = 1710p

Income: 90×11+150×10=249090 \times 11 + 150 \times 10 = 2490p

Profit: 2490−1710=7802490 - 1710 = 780p

7801710×100=45.6%\frac{780}{1710} \times 100 = 45.6\%

Watch out: Dividing the profit by the selling total instead of the cost.

Percentage change and reverse percentages2 marksGrade 5CalculatorHigher
November 2024 · Paper 3 Higher · Q10
Find an original price given the sale price after a percentage reduction.

© Pearson Education Ltd. November 2024 Paper 3 (Higher, calculator), question 10.

Show answer
Answer£552 marks

Worked solution Checked against the mark scheme

After a 15% reduction the sale price is 85% of the normal price.

Normal price =46.75÷0.85=£55= 46.75 \div 0.85 = £55

Watch out: Adding 15% to £46.75 to get £53.76.

Percentage change and reverse percentages2 marksGrade 5No calculatorHigher
November 2023 · Paper 1 Higher · Q8
Find an original price after a 40% reduction, given the sale price.

© Pearson Education Ltd. November 2023 Paper 1 (Higher, non-calculator), question 8.

Show answer
Answer£11002 marks

Worked solution Checked against the mark scheme

The sale price is 100%−40%=60%100\% - 40\% = 60\% of the normal price.

60%60\% is £660, so 1%1\% is £11 and 100%100\% is £1100

Watch out: Adding 40% of 660 to get £924.

Percentage change and reverse percentages4 marksGrade 5CalculatorOn both tiers
November 2023 · Paper 2 Foundation · Q23
Work out the percentage profit from ticket sales after event costs.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 23.

Show answer
Answer35%4 marks

Worked solution Checked against the mark scheme

Income: 54×7.50=£40554 \times 7.50 = £405

Costs: 100+120+80=£300100 + 120 + 80 = £300

Profit: 405−300=£105405 - 300 = £105

Percentage profit =105300×100=35%= \frac{105}{300} \times 100 = 35\%

Watch out: Dividing the profit by the income (405) instead of the costs.

Percentage change and reverse percentages2 marksGrade 5CalculatorFoundation
November 2022 · Paper 2 Foundation · Q26
Use a reverse percentage to find a population before a percentage increase.

© Pearson Education Ltd. November 2022 Paper 2 (Foundation, calculator), question 26.

Show answer
Answer1520002 marks

Worked solution Checked against the mark scheme

After the increase the population is 109% of the 2018 figure.

165680÷1.09=152000165680 \div 1.09 = 152000

Watch out: Taking 9% off 165 680 to get 150 768.8.

Percentage change and reverse percentages3 marksGrade 5CalculatorHigher
November 2022 · Paper 2 Higher · Q8
Work out the percentage profit when an item is bought for £120 and sold for £135.

© Pearson Education Ltd. November 2022 Paper 2 (Higher, calculator), question 8.

Show answer
Answer12.5%12.5\%3 marks

Worked solution Checked against the mark scheme

Profit =135−120=£15= 135 - 120 = £15

Percentage profit =15120×100=12.5%= \frac{15}{120} \times 100 = 12.5\%

Watch out: Dividing by the selling price, 15 ÷ 135, giving 11.1%.

Percentage change and reverse percentages2 marksGrade 5CalculatorFoundation
June 2022 · Paper 3 Foundation · Q30
Find the original value of a car after a 15% decrease.

© Pearson Education Ltd. June 2022 Paper 3 (Foundation, calculator), question 30.

Show answer
Answer£16 0002 marks

Worked solution Checked against the mark scheme

After a 15% decrease the car is worth 85% of the original.

0.85×original=13 6000.85 \times \text{original} = 13\,600

Original =13 600÷0.85=£16 000= 13\,600 \div 0.85 = £16\,000

Watch out: Adding 15% of £13 600 to get £15 640.

Percentage change and reverse percentages2 marksGrade 5CalculatorFoundation
November 2021 · Paper 2 Foundation · Q28
Find the original price after a percentage decrease.

© Pearson Education Ltd. November 2021 Paper 2 (Foundation, calculator), question 28.

Show answer
Answer£320 0002 marks

Worked solution Checked against the mark scheme

The sale price is 100%−15%=85%100\% - 15\% = 85\% of the normal price.

272 000÷0.85=£320 000272\,000 \div 0.85 = £320\,000

Watch out: Adding 15% of £272 000 to get £312 800.

Percentage change and reverse percentages5 marksGrade 5CalculatorHigher
November 2020 · Paper 2 Higher · Q8
Find an original price after a 5% discount, then find the value of a savings investment with different compound interest rates in different years.

© Pearson Education Ltd. November 2020 Paper 2 (Higher, calculator), question 8.

Show answer
(a)£5802 marks
(b)£6354.673 marks

Worked solution Checked against the mark scheme

(a) £551 is 95% of the normal price: 551÷0.95=580551 \div 0.95 = 580, so £580.

(b) After year 1: 6000×1.024=61446000 \times 1.024 = 6144.

Years 2 and 3: 6144×1.0172=6354.676144 \times 1.017^2 = 6354.67.

The investment is worth £6354.67.

Watch out: In (a), finding 5% of £551 and adding it on, giving £578.55.

Percentage change and reverse percentages5 marksGrade 5No calculatorOn both tiers
November 2018 · Paper 1 Foundation · Q22
Test a claim that sharing a bonus equally would give a salesman 25% more.

© Pearson Education Ltd. November 2018 Paper 1 (Foundation, non-calculator), question 22.

Show answer
AnswerNo: he would get £210 instead of £180, only about 16.7% more (25% more would be £225)5 marks

Worked solution Checked against the mark scheme

Managers get 0.4×2100=£8400.4 \times 2100 = £840, so salesmen get 2100−840=£12602100 - 840 = £1260.

Each salesman: 1260÷7=£1801260 \div 7 = £180.

Shared equally: 2100÷10=£2102100 \div 10 = £210.

25% more than £180 is 180×1.25=£225180 \times 1.25 = £225.

£210≠£225£210 \ne £225, so the salesman is wrong (it is only about 16.7% more).

Watch out: Working out 25% of the whole bonus rather than of one salesman's share.

Percentage change and reverse percentages4 marksGrade 5No calculatorFoundation
June 2018 · Paper 1 Foundation · Q21
Work out the percentage profit when sweets are bought in bulk and sold in bags.

© Pearson Education Ltd. June 2018 Paper 1 (Foundation, non-calculator), question 21.

Show answer
Answer30%30\%4 marks

Worked solution Checked against the mark scheme

5 kg =5000= 5000 g, so 5000÷250=205000 \div 250 = 20 bags

Takings =20×65p=£13= 20 \times 65\text{p} = £13

Profit =13−10=£3= 13 - 10 = £3

Percentage profit =310×100=30%= \frac{3}{10} \times 100 = 30\%

Watch out: Giving 130% (takings as a percentage of cost).

Percentage change and reverse percentages3 marksGrade 5CalculatorOn both tiers
June 2018 · Paper 2 Foundation · Q25
Decide whether a pressure falls by less than 20% when force and area both increase.

© Pearson Education Ltd. June 2018 Paper 2 (Foundation, calculator), question 25.

Show answer
AnswerNo: pressure falls from 3.53.5 to 2.672.67 N/cm², a decrease of about 24%3 marks

Worked solution Checked against the mark scheme

Original pressure: 70÷20=3.570 \div 20 = 3.5 N/cm²

New pressure: 80÷30=2.6780 \div 30 = 2.67 N/cm²

Decrease: 3.5−2.67=0.833.5 - 2.67 = 0.83

Percentage decrease: 0.833.5×100≈24%\frac{0.83}{3.5} \times 100 \approx 24\%

This is more than 20%, so Helen is wrong.

Watch out: Comparing the 10 N and 10 cm² increases directly without working out pressures.

Percentage change and reverse percentages3 marksGrade 5CalculatorHigher
June 2018 · Paper 3 Higher · Q11
Work backwards through a 10% loss and a 20% profit to find a house's original price.

© Pearson Education Ltd. June 2018 Paper 3 (Higher, calculator), question 11.

Show answer
Answer£150 0003 marks

Worked solution Checked against the mark scheme

Mia's sale was 90% of her price: 162 000÷0.9=180 000162\,000 \div 0.9 = 180\,000

Jerry's sale was 120% of his price: 180 000÷1.2=150 000180\,000 \div 1.2 = 150\,000

Jerry paid £150 000.

Watch out: Adding 10% then subtracting 20% instead of dividing by the multipliers.

Percentage change and reverse percentages2 marksGrade 5No calculatorFoundation
June 2024 · Paper 1 Foundation · Q27
Find an original price from a sale price after a percentage reduction.

© Pearson Education Ltd. June 2024 Paper 1 (Foundation, non-calculator), question 27.

Show answer
Answer£4002 marks

Worked solution Checked against the mark scheme

After a 30% reduction the sale price is 70% of the normal price.

70%=£28070\% = £280, so 10%=£4010\% = £40 and 100%=£400100\% = £400.

Watch out: Adding 30% of £280 to get £364.

Percentage change and reverse percentages3 marksGrade 6No calculatorHigher
June 2019 · Paper 1 Higher · Q12
Two successive 50% increases link three volumes; express the first volume as a fraction of the last.

© Pearson Education Ltd. June 2019 Paper 1 (Higher, non-calculator), question 12.

Show answer
Answer49\frac{4}{9}3 marks

Worked solution Checked against the mark scheme

Q=1.5PQ = 1.5P and R=1.5Q=1.52P=2.25PR = 1.5Q = 1.5^2 P = 2.25P

PR=12.25=49\frac{P}{R} = \frac{1}{2.25} = \frac{4}{9}

Watch out: Adding the percentages to get a 100% increase and answering 12\frac{1}{2}.

Percentage change and reverse percentages5 marksGrade 6CalculatorHigher
November 2018 · Paper 2 Higher · Q10
Find the cost of mixing paint from tins in a given ratio and work out the percentage profit on each tin sold.

© Pearson Education Ltd. November 2018 Paper 2 (Higher, calculator), question 10.

Show answer
Answer35%5 marks

Worked solution Checked against the mark scheme

Yellow =25×50=20= \frac{2}{5} \times 50 = 20 litres = 4 tins; blue =30= 30 litres = 3 tins.

Cost =4×26+3×48=104+144=£248= 4 \times 26 + 3 \times 48 = 104 + 144 = £248 for 50 litres.

Cost per 10 litre tin =248÷5=£49.60= 248 \div 5 = £49.60.

Profit =66.96−49.60=£17.36= 66.96 - 49.60 = £17.36

17.3649.60×100=35%\frac{17.36}{49.60} \times 100 = 35\%

Watch out: Dividing the profit by the selling price (66.96) instead of the cost.

Percentage change and reverse percentages3 marksGrade 7No calculatorHigher
November 2018 · Paper 1 Higher · Q11
Find the percentage price cut that matches the value for money of putting 25% more cereal in a box.

© Pearson Education Ltd. November 2018 Paper 1 (Higher, non-calculator), question 11.

Show answer
Answer2020%3 marks

Worked solution Checked against the mark scheme

Jack: 125 g for the price of 100 g, so 1 g costs 100125=0.8\frac{100}{125} = 0.8 of the old price.

Sadia needs the price of the normal box to be 80% of the original.

Reduction =100%−80%=20%= 100\% - 80\% = 20\%

Watch out: Answering 25%.

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