Edexcel GCSE Maths · 1MA1

June 2024 Paper 3 Foundation

Calculator · 29 questions · 80 marks · 1 hour 30 minutes. Try each question on paper, then press "Show answer".

Question 1

Convert a percentage into a fraction.

© Pearson Education Ltd. June 2024 Paper 3 (Foundation, calculator), question 1.

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Answer23100\frac{23}{100}1 mark

Worked solution Checked against the mark scheme

Per cent means 'out of 100', so 23%=2310023\% = \frac{23}{100}.

Watch out: Writing 0.23 or 23/10 instead of a fraction out of 100.

Question 2

Units and converting units1 markGrade 1Calculator
Convert a length from centimetres to metres.

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Answer88 metres1 mark

Worked solution Checked against the mark scheme

There are 100 cm in 1 m.

800÷100=8800 \div 100 = 8 m

Watch out: Multiplying by 100 to get 80 000.

Question 3

State the place value of a digit in a five-digit number.

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Answertens (or 3030)1 mark

Worked solution Checked against the mark scheme

In 62 837 the digits are: 6 ten-thousands, 2 thousands, 8 hundreds, 3 tens, 7 units.

So the 3 is worth 3 tens, i.e. 3030.

Watch out: Answering 3, or saying hundreds.

Question 4

Expanding brackets and simplifying1 markGrade 2Calculator
Simplify an expression by collecting like terms.

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Answer3a3a1 mark

Worked solution Checked against the mark scheme

7a+a=8a7a + a = 8a

8a−5a=3a8a - 5a = 3a

Watch out: Forgetting that aa means 1a1a, giving 2a2a.

Question 5

Put three simple fractions in order from smallest to largest.

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Answer14, 12, 23\frac14,\ \frac12,\ \frac231 mark

Worked solution Checked against the mark scheme

Convert to decimals: 12=0.5\frac12 = 0.5, 23≈0.67\frac23 \approx 0.67, 14=0.25\frac14 = 0.25.

Smallest first: 14, 12, 23\frac14,\ \frac12,\ \frac23

Watch out: Thinking a bigger denominator means a bigger fraction, so putting 14\frac14 last.

Question 6

Use a map scale to find a real distance and a map length.

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(a)3232 km2 marks
(b)2.52.5 cm (or 25 mm)2 marks

Worked solution Checked against the mark scheme

(a) Each 1 cm is 4 km, so 8×4=328 \times 4 = 32 km.

(b) 10÷4=2.510 \div 4 = 2.5, so the road is 2.52.5 cm long on the map.

Watch out: Leaving off the units in (b), which loses the accuracy mark.

Question 7

Charts, graphs and time series2 marksGrade 1Calculator
Read a bar chart to find the mode and the difference between two categories.

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(a)Bus1 mark
(b)551 mark

Worked solution Checked against the mark scheme

(a) The tallest bar is Bus (9 students), so the mode is Bus.

(b) Walk = 8, Cycle = 3, so 8−3=58 - 3 = 5 more.

Watch out: Giving the frequency 9 instead of the category for the mode.

Question 8

Decide whether an election falls in a given year using a repeating 5-year pattern starting from an 18th birthday.

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AnswerNo, with correct figures (elections in 2011, 2016, 2021, 2026, 2031)3 marks

Worked solution Checked against the mark scheme

Aisha's 18th birthday: 1993+18=20111993 + 18 = 2011.

Elections every 5 years: 2011, 2016, 2021, 2026, 2031.

2030 is not in the list, so No, there will not be an election in 2030.

Watch out: Counting 5-year steps from 1993 instead of from 2011.

Question 9

Show that a total holiday cost made of daily and hourly charges is within a budget of £500.

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AnswerTotal is £498, which is less than £500, so she has enough3 marks

Worked solution Checked against the mark scheme

Ski hire: 5×26=£1305 \times 26 = £130

Lift pass: 4×45=£1804 \times 45 = £180

Lessons: 8×23.50=£1888 \times 23.50 = £188

Total: 130+180+188=£498130 + 180 + 188 = £498, and 498<500498 < 500, so Lucia has enough money.

Watch out: Using the same number of days for every item.

Question 10

Draw a radius on a circle and name a line inside a circle.

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(a)A straight line from the centre to the circumference1 mark
(b)chord1 mark

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(a) A radius joins the centre of the circle to any point on the edge.

(b) A straight line joining two points on the circumference (not through the centre) is a chord.

Watch out: Drawing a diameter instead of a radius, or calling the line a diameter.

Question 11

Units and converting units2 marksGrade 2Calculator
Find the total time of several episodes and give it in hours.

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Answer66 hours2 marks

Worked solution Checked against the mark scheme

8×45=3608 \times 45 = 360 minutes

360÷60=6360 \div 60 = 6 hours

Watch out: Dividing by 100 instead of 60, giving 3.6 hours.

Question 12

Factors, multiples and primes2 marksGrade 2Calculator
List three prime numbers between 20 and 40.

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AnswerAny three of 23,29,31,3723, 29, 31, 372 marks

Worked solution Checked against the mark scheme

Check each odd number from 21 to 39 for factors:

21, 25, 27, 33, 35, 39 all have factors other than 1 and themselves.

The primes are 23,29,31,3723, 29, 31, 37, so any three of these.

Watch out: Including 27 or 39, which are multiples of 3.

Question 13

Charts, graphs and time series3 marksGrade 2Calculator
Complete a two-way table using row and column totals.

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AnswerYear 10: French 33, German 27, Spanish 34, Total 94; Year 11: French 35, German 45, Spanish 33, Total 113; Totals: 68, 72, 67, 2073 marks

Worked solution Checked against the mark scheme

Spanish Year 11: 67−34=3367 - 34 = 33

French Year 11: 113−45−33=35113 - 45 - 33 = 35

Year 10 total: 207−113=94207 - 113 = 94

German Year 10: 94−33−34=2794 - 33 - 34 = 27

French total: 33+35=6833 + 35 = 68; German total: 27+45=7227 + 45 = 72 (check: 68+72+67=20768 + 72 + 67 = 207)

Watch out: Filling a cell before enough information is known and then not checking the totals.

Question 14

Charts, graphs and time series3 marksGrade 3Calculator
Draw a pie chart from a frequency table of drinks.

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AnswerPie chart with Coffee 120°120°, Hot chocolate 40°40°, Tea 200°200°, each sector labelled3 marks

Worked solution Checked against the mark scheme

Total people: 30+10+50=9030 + 10 + 50 = 90

Each person: 360÷90=4°360 \div 90 = 4°

Coffee 30×4=120°30 \times 4 = 120°, Hot chocolate 10×4=40°10 \times 4 = 40°, Tea 50×4=200°50 \times 4 = 200°

Draw each angle with a protractor and label each sector with the drink.

Watch out: Labelling sectors with angles instead of drink names.

Question 15

Percentages3 marksGrade 3Calculator
Compare two percentages of amounts to decide which is greater.

© Pearson Education Ltd. June 2024 Paper 3 (Foundation, calculator), question 15.

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Answer15% of 88, since 13.2>12.413.2 > 12.43 marks

Worked solution Checked against the mark scheme

15%15\% of 88=0.15×88=13.288 = 0.15 \times 88 = 13.2

20%20\% of 62=0.2×62=12.462 = 0.2 \times 62 = 12.4

13.2>12.413.2 > 12.4, so 15% of 88 is greater.

Watch out: Assuming 20% must give the bigger answer without calculating.

Question 16

Simplify a repeated product using index notation and form an expression for total points.

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(a)m4m^41 mark
(b)5x+2y5x + 2y2 marks

Worked solution Checked against the mark scheme

(a) mm multiplied by itself 4 times is m4m^4.

(b) Wins score 5×x=5x5 \times x = 5x, draws score 2×y=2y2 \times y = 2y, losses score 0.

Total: 5x+2y5x + 2y

Watch out: Writing 4m4m in (a), or 7xy7xy in (b).

Question 17

Direct and inverse proportion3 marksGrade 3Calculator
Scale up a recipe from 20 biscuits to 30 biscuits.

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Answerbutter 180180 g, flour 300300 g, sugar 7575 g3 marks

Worked solution Checked against the mark scheme

Scale factor: 30÷20=1.530 \div 20 = 1.5

Butter: 120×1.5=180120 \times 1.5 = 180 g

Flour: 200×1.5=300200 \times 1.5 = 300 g

Sugar: 50×1.5=7550 \times 1.5 = 75 g

Watch out: Adding 10 g to each amount instead of multiplying.

Question 18

Transformations3 marksGrade 3Calculator
Rotate a shape 180° about the origin and explain why a reflection in x = 3 is wrong.

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(a)Trapezium with vertices (−4,−2),(−2,−2),(−1,−4),(−5,−4)(-4,-2), (-2,-2), (-1,-4), (-5,-4)2 marks
(b)He reflected in the line y=3y = 3 instead of x=3x = 3 (the line x=3x = 3 is vertical)1 mark

Worked solution Checked against the mark scheme

(a) A 180° rotation about (0,0)(0,0) sends (x,y)(x, y) to (−x,−y)(-x, -y).

(1,4)→(−1,−4)(1,4)\to(-1,-4), (5,4)→(−5,−4)(5,4)\to(-5,-4), (4,2)→(−4,−2)(4,2)\to(-4,-2), (2,2)→(−2,−2)(2,2)\to(-2,-2). Join these points.

(b) x=3x = 3 is a vertical line through 3 on the xx-axis. Mike's image is below A, so he reflected in the horizontal line y=3y = 3.

Watch out: Confusing x=3x = 3 (vertical) with y=3y = 3 (horizontal).

Question 19

Coordinates and straight-line graphs3 marksGrade 3Calculator
Draw the graph of a linear equation for a given range of x values.

© Pearson Education Ltd. June 2024 Paper 3 (Foundation, calculator), question 19.

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AnswerStraight line through (−2,−8),(−1,−5),(0,−2),(1,1),(2,4),(3,7)(-2,-8), (-1,-5), (0,-2), (1,1), (2,4), (3,7)3 marks

Worked solution Checked against the mark scheme

Make a table using y=3x−2y = 3x - 2:

| xx | −2 | −1 | 0 | 1 | 2 | 3 |
|---|---|---|---|---|---|---|
| yy | −8 | −5 | −2 | 1 | 4 | 7 |

Plot the points and join them with a ruler from x=−2x = -2 to x=3x = 3.

Watch out: Working out 3×(−2)3 \times (-2) as +6+6, giving the wrong negative points.

Question 20

Angle facts and parallel lines5 marksGrade 5Calculator
Use isosceles triangle angle facts to find two angles and write them as a ratio 1 : n.

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Answer1:31 : 35 marks

Worked solution Checked against the mark scheme

In triangle ABC, AB=BCAB = BC so angle BCA = angle CAB = 81°81°.

Angle ABC =180−2×81=18°= 180 - 2 \times 81 = 18°

Angle BCD =4×18=72°= 4 \times 18 = 72°

In triangle BCD, BC=CDBC = CD so angle CBD = angle CDB =(180−72)÷2=54°= (180 - 72) \div 2 = 54°

18:54=1:318 : 54 = 1 : 3

Watch out: Putting the equal angles in the wrong place in triangle BCD (they are opposite the equal sides BC and CD).

Question 21

Factorising2 marksGrade 4Calculator
Factorise a linear expression and a simple quadratic expression.

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(a)3(2x−5)3(2x - 5)1 mark
(b)m(m+5)m(m + 5)1 mark

Worked solution Checked against the mark scheme

(a) The HCF of 6 and 15 is 3: 6x−15=3(2x−5)6x - 15 = 3(2x - 5)

(b) Both terms contain mm: m2+5m=m(m+5)m^2 + 5m = m(m + 5)

Watch out: Only partly factorising, or writing m(m+5m)m(m + 5m).

Question 22

Factors, multiples and primes2 marksGrade 3CalculatorOn both tiers
Find the highest common factor of two numbers.

© Pearson Education Ltd. June 2024 Paper 3 (Foundation, calculator), question 22.

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Answer21212 marks

Worked solution Checked against the mark scheme

63=3×3×763 = 3 \times 3 \times 7

105=3×5×7105 = 3 \times 5 \times 7

Common prime factors: 3×7=213 \times 7 = 21

Watch out: Giving just one common prime factor (3 or 7), or finding the LCM.

Question 23

Standard form4 marksGrade 4CalculatorOn both tiers
Convert between standard form and ordinary numbers, and add two numbers in standard form.

© Pearson Education Ltd. June 2024 Paper 3 (Foundation, calculator), question 23.

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(a(i))53 00053\,0001 mark
(a(ii))0.000 0740.000\,0741 mark
(b)3.42×1073.42 \times 10^72 marks

Worked solution Checked against the mark scheme

(a)(i) Move the decimal point 4 places right: 53 00053\,000

(a)(ii) Move the decimal point 5 places left: 0.000 0740.000\,074

(b) 9 700 000+24 500 000=34 200 000=3.42×1079\,700\,000 + 24\,500\,000 = 34\,200\,000 = 3.42 \times 10^7

Watch out: Adding the numbers in front and the powers separately, e.g. 12.15×101312.15 \times 10^{13}.

Question 24

3D shapes, plans and elevations3 marksGrade 4CalculatorOn both tiers
Explain why a side elevation of a triangular prism is wrong and draw its plan.

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(a)The height should be less than 4 cm (the perpendicular height, 7≈2.6\sqrt7 \approx 2.6 cm), not the 4 cm sloping edge1 mark
(b)A 7 cm by 6 cm rectangle with a line parallel to the 7 cm sides through the middle (3 cm from each side)2 marks

Worked solution Checked against the mark scheme

(a) Rana drew a 7 cm by 4 cm rectangle. The 4 cm sides of the triangle slope, so the prism is not 4 cm tall. Its height is 42−32=7≈2.6\sqrt{4^2 - 3^2} = \sqrt7 \approx 2.6 cm.

(b) From above you see the 6 cm by 7 cm base. The top edge (ridge) is above the middle of the 6 cm side, so draw a 7 cm by 6 cm rectangle with a line along its length 3 cm from each long side.

Watch out: Leaving out the ridge line in the plan.

Question 25

Compound interest, growth and decay4 marksGrade 5CalculatorOn both tiers
Work out the number of workers after 3 years of 6% compound growth.

© Pearson Education Ltd. June 2024 Paper 3 (Foundation, calculator), question 25.

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Answer29 77529\,775 (accept 29 77629\,776, 29 78029\,780, 29 80029\,800)4 marks

Worked solution Checked against the mark scheme

Multiplier for a 6% increase: 1.061.06

25 000×1.063=29 775.425\,000 \times 1.06^3 = 29\,775.4

So about 29 77529\,775 workers.

Watch out: Using simple interest: 25 000+3×1500=29 50025\,000 + 3 \times 1500 = 29\,500.

Question 26

Speed, density and pressure4 marksGrade 5CalculatorOn both tiers
Use a density to find the volume of a tin, then find the density of salt that part-fills it.

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Answer22 g/cm³4 marks

Worked solution Checked against the mark scheme

Volume of tin =massdensity=600÷0.6=1000= \frac{\text{mass}}{\text{density}} = 600 \div 0.6 = 1000 cm³

Volume of salt =1000−700=300= 1000 - 700 = 300 cm³

Density of salt =600÷300=2= 600 \div 300 = 2 g/cm³

Watch out: Using 700 cm³ as the volume of salt.

Question 27

Tree diagrams and combined events4 marksGrade 4CalculatorOn both tiers
Complete a probability tree for two biased coins and find the probability both land heads.

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(a)Coin A not heads 0.40.4; coin B branches 0.450.45, 0.550.55, 0.450.452 marks
(b)0.330.332 marks

Worked solution Checked against the mark scheme

(a) 1−0.6=0.41 - 0.6 = 0.4 and 1−0.55=0.451 - 0.55 = 0.45. Each coin B pair of branches is 0.550.55 (heads) and 0.450.45 (not heads).

(b) P(both heads)=0.6×0.55=0.33P(\text{both heads}) = 0.6 \times 0.55 = 0.33

Watch out: Adding the probabilities (0.6+0.550.6 + 0.55) instead of multiplying.

Question 28

Volume and surface area4 marksGrade 5CalculatorOn both tiers
Find the volume of a cylindrical pool and how many minutes it takes to fill at a given rate.

© Pearson Education Ltd. June 2024 Paper 3 (Foundation, calculator), question 28.

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Answer6363 minutes (accept 62 to 63)4 marks

Worked solution Checked against the mark scheme

Volume =πr2h=π×1002×30=942 478= \pi r^2 h = \pi \times 100^2 \times 30 = 942\,478 cm³

Time =942 478÷250=3769.9= 942\,478 \div 250 = 3769.9 seconds

3769.9÷60=62.83769.9 \div 60 = 62.8, so about 6363 minutes.

Watch out: Using the diameter or forgetting to square the radius; or giving the time in seconds.

Question 29

Formulae and changing the subject4 marksGrade 4Calculator
Substitute a negative value into a formula and rearrange a formula to change its subject.

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(a)w=15w = 152 marks
(b)h=3p+5h = 3p + 52 marks

Worked solution Checked against the mark scheme

(a) w=40−(−5)2=40−25=15w = 40 - (-5)^2 = 40 - 25 = 15

(b) p=h−53p = \frac{h - 5}{3}

Multiply by 3: 3p=h−53p = h - 5

Add 5: h=3p+5h = 3p + 5

Watch out: In (a), working out −52-5^2 as −25-25 to get 6565.

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