Edexcel GCSE Maths · 1MA1

November 2022 Paper 3 Foundation

Calculator · 30 questions · 80 marks · 1 hour 30 minutes. Try each question on paper, then press "Show answer".

Question 1

Put four decimals in ascending order.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 1.

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Answer0.408, 0.41, 0.46, 0.51 mark

Worked solution Checked against the mark scheme

Give each number three decimal places: 0.410, 0.500, 0.460, 0.408.

Now compare: 0.408 < 0.410 < 0.460 < 0.500, so the order is 0.408, 0.41, 0.46, 0.5

Watch out: Thinking 0.408 is bigger than 0.41 because it has more digits.

Question 2

State what the digit 2 is worth in a five-digit number.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 2.

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Answer20001 mark

Worked solution Checked against the mark scheme

In 12 345 the digits are: 1 ten-thousand, 2 thousands, 3 hundreds, 4 tens, 5 ones.

So the 2 is worth 2000.

Watch out: Writing just 2 or 'hundreds'.

Question 3

Convert the fraction four-fifths to a decimal.

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Answer0.80.81 mark

Worked solution Checked against the mark scheme

45=810=0.8\frac{4}{5} = \frac{8}{10} = 0.8

Watch out: Writing 0.45 by putting the digits after the point.

Question 4

Rounding and estimation1 markGrade 1Calculator
Round a decimal to the nearest whole number.

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Answer191 mark

Worked solution Checked against the mark scheme

Look at the first decimal place: 19.4949. It is 4, which is less than 5, so round down.

Answer: 19

Watch out: Rounding each digit in turn from the right and getting 20.

Question 5

Factors, multiples and primes1 markGrade 1Calculator
Pick out a multiple of 3 from a list of numbers.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 5.

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Answer181 mark

Worked solution Checked against the mark scheme

Check each number: 18=3×618 = 3 \times 6, and none of 5, 11, 22 or 29 divides exactly by 3.

Answer: 18

Watch out: Choosing 11 or 29 because they are odd.

Question 6

Charts, graphs and time series2 marksGrade 1Calculator
Read a line graph of monthly temperatures to count months above a value and find two equal months.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 6.

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(a)61 mark
(b)May and October1 mark

Worked solution Checked against the mark scheme

(a) Months above 16°C: May, Jun, Jul, Aug, Sep, Oct, so 6 months (April is exactly 16°C, not above).

(b) May and October are both at 20°C.

Watch out: Counting April, which is exactly 16°C, not greater than it.

Question 7

Fractions3 marksGrade 3Calculator
Find the total takings when a quarter of the bars sell at one price and the rest at another.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 7.

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Answer£145.603 marks

Worked solution Checked against the mark scheme

Large bars: 208÷4=52208 \div 4 = 52, worth 52×£1=£5252 \times £1 = £52

Small bars: 208−52=156208 - 52 = 156, worth 156×£0.60=£93.60156 \times £0.60 = £93.60

Total: £52+£93.60=£145.60£52 + £93.60 = £145.60

Watch out: Mixing pence and pounds and writing £9412 or £145.6.

Question 8

Averages and spread3 marksGrade 2Calculator
Find the difference between two scores in a table and the mean of all four scores.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 8.

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(a)1021 mark
(b)822 marks

Worked solution Checked against the mark scheme

(a) 121−19=102121 - 19 = 102

(b) Total =143+121+45+19=328= 143 + 121 + 45 + 19 = 328

Mean =328÷4=82= 328 \div 4 = 82

Watch out: Dividing the total by a number other than 4.

Question 9

Coordinates and straight-line graphs3 marksGrade 2Calculator
Read the coordinates of a point, plot a given point and draw a horizontal line on a coordinate grid.

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(a)(−1,2)(-1, 2)1 mark
(b)Point B plotted at (1,4)(1, 4)1 mark
(c)Horizontal line through y=−3y = -31 mark

Worked solution Checked against the mark scheme

(a) A is 1 left of O and 2 up, so A is (−1,2)(-1, 2).

(b) Go 1 right, then 4 up, and mark B.

(c) y=−3y = -3 is the horizontal line where every point has y-coordinate −3.

Watch out: Drawing a vertical line through x = −3 for y = −3.

Question 10

Sequences and the nth term2 marksGrade 2Calculator
Continue a sequence with falling differences and describe the rule used.

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(i)e.g. 11, 10 (differences 4, 3, 2, 1) or 9, 61 mark
(ii)e.g. the amount subtracted goes down by 1 each time1 mark

Worked solution Checked against the mark scheme

The differences are 20−16=420 - 16 = 4 and 16−13=316 - 13 = 3.

If the differences keep falling by 1, next subtract 2 then 1: 13−2=1113 - 2 = 11, 11−1=1011 - 1 = 10.

Rule: the number you take away goes down by 1 each time.

Watch out: Saying 'it goes down by 1 each time', which does not describe the terms.

Question 11

Volume and surface area2 marksGrade 2Calculator
Work out the volume of a cuboid from its three dimensions.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 11.

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Answer160 cm³2 marks

Worked solution Checked against the mark scheme

Volume =8×5×4=160 cm3= 8 \times 5 \times 4 = 160\text{ cm}^3

Watch out: Adding the lengths or finding surface area instead.

Question 12

Ratio2 marksGrade 3Calculator
Write a three-part ratio from statements about how many sweets each person has compared with another.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 12.

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Answer1:6:31 : 6 : 32 marks

Worked solution Checked against the mark scheme

Let Amol have 1 sweet. Gemma has 6×1=66 \times 1 = 6. Harry has 6÷2=36 \div 2 = 3.

Ratio: 1:6:31 : 6 : 3

Watch out: Writing 1 : 6 : 12 by doubling instead of halving.

Question 13

Angles in polygons3 marksGrade 3Calculator
Find a missing angle in a quadrilateral with a reason, and explain why a triangle's labelled angles are impossible.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 13.

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(a(i))40°1 mark
(a(ii))Angles in a quadrilateral add up to 360°1 mark
(b)80+60+50=19080 + 60 + 50 = 190, but angles in a triangle add up to 180°1 mark

Worked solution Checked against the mark scheme

(a) x=360−120−120−80=40°x = 360 - 120 - 120 - 80 = 40° because the angles in a quadrilateral add up to 360°.

(b) 80+60+50=190°80 + 60 + 50 = 190°. Angles in a triangle must add up to 180°, so the diagram cannot be right.

Watch out: Using 180° for the quadrilateral.

Question 14

Use a conversion graph between grams and ounces, including a value beyond the graph.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 14.

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(a)30 ounces1 mark
(b)About 2270 grams (2238–2296)2 marks

Worked solution Checked against the mark scheme

(a) Across from 850 g to the line, then down: 30 ounces.

(b) 80 is off the graph, so use 20 ounces: 20 ounces ≈ 567 g.

80=4×2080 = 4 \times 20, so 4×567≈22684 \times 567 \approx 2268 g.

Watch out: Reading 80 ounces as if it were on the graph, or adding instead of multiplying.

Question 15

Direct and inverse proportion5 marksGrade 4Calculator
Use the cost of carrots to find the price of onions and decide whether £2 buys 4 kg of onions.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 15.

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AnswerYes: 4 kg of onions cost £1.925 marks

Worked solution Checked against the mark scheme

Carrots: 1.74÷3=£0.581.74 \div 3 = £0.58 per kg, so 2 kg cost £1.16£1.16

Onions: 2.36−1.16=£1.202.36 - 1.16 = £1.20 for 2.5 kg, so 1.20÷2.5=£0.481.20 \div 2.5 = £0.48 per kg

4 kg: 4×0.48=£1.924 \times 0.48 = £1.92, which is less than £2, so yes.

Watch out: Dividing £2.36 by 4.5 kg as if onions and carrots cost the same.

Question 16

Charts, graphs and time series2 marksGrade 3Calculator
Criticise a pie chart drawn from a frequency table.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 16.

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AnswerThe sectors have no labels (or no key); the angles are wrong (should be 108°, 126°, 126°)2 marks

Worked solution Checked against the mark scheme

Total =90+105+105=300= 90 + 105 + 105 = 300 potatoes, so each potato is 360÷300=1.2°360 \div 300 = 1.2°.

Correct angles: 90×1.2=108°90 \times 1.2 = 108°, 105×1.2=126°105 \times 1.2 = 126° twice. Salim's sectors are clearly not these sizes (one is a right angle), so they are wrong.

Also, the sectors are not labelled with the types of potato.

Watch out: Only saying 'the sectors are the wrong size' without a reason.

Question 17

Rounding and estimation3 marksGrade 3Calculator
Round to three significant figures and evaluate a fraction with brackets on a calculator.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 17.

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(a)87 6001 mark
(b)13.5242 marks

Worked solution Checked against the mark scheme

(a) The 4th figure is 6, so round the 5 up: 87 600

(b) Top: (3.2+3.7)×4.9=6.9×4.9=33.81(3.2 + 3.7) \times 4.9 = 6.9 \times 4.9 = 33.81

Bottom: 5.3−2.8=2.55.3 - 2.8 = 2.5

33.81÷2.5=13.52433.81 \div 2.5 = 13.524

Watch out: In (a) writing 876 without the zeros to keep place value.

Question 18

Transformations2 marksGrade 4Calculator
Rotate a shape 90° anticlockwise about the origin on a grid.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 18.

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AnswerVertices at (2,−1)(2,-1), (2,−4)(2,-4), (4,−2)(4,-2), (4,−1)(4,-1)2 marks

Worked solution Checked against the mark scheme

The shape has vertices (−4,−2)(-4,-2), (−1,−2)(-1,-2), (−1,−4)(-1,-4), (−2,−4)(-2,-4).

A 90° anticlockwise turn about O sends (x,y)(x, y) to (−y,x)(-y, x).

New vertices: (2,−4)(2,-4), (2,−1)(2,-1), (4,−1)(4,-1), (4,−2)(4,-2).

Watch out: Rotating clockwise instead of anticlockwise.

Question 19

Read a distance-time graph to find a stop time and a distance, and calculate a speed.

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(a)15 minutes1 mark
(b)4.6 km (4.4–4.8)1 mark
(c)12 km/h2 marks

Worked solution Checked against the mark scheme

(a) The line is flat from 08 30 to 08 45: 15 minutes.

(b) At 08 50 the graph is at about 4.6 km.

(c) She travels 4 km in 20 minutes. 20 minutes =13= \frac{1}{3} hour.

Speed =4÷13=12= 4 \div \frac{1}{3} = 12 km/h

Watch out: Giving 0.2 (km per minute) instead of converting to km/h.

Question 20

Direct and inverse proportion4 marksGrade 4Calculator
Scale a recipe up and work out how much more of each ingredient is needed.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 20.

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Answer100 g more butter, 25 g more sugar, 1 more egg4 marks

Worked solution Checked against the mark scheme

Scale factor: 25÷10=2.525 \div 10 = 2.5

Butter 80×2.5=20080 \times 2.5 = 200 g, flour 350×2.5=875350 \times 2.5 = 875 g, sugar 30×2.5=7530 \times 2.5 = 75 g, eggs 2×2.5=52 \times 2.5 = 5

Compare: butter 200−100=100200 - 100 = 100 g more, sugar 75−50=2575 - 50 = 25 g more, eggs 5−4=15 - 4 = 1 more. Flour is fine (875 g < 1 kg).

Watch out: Working out the full amounts needed instead of how much more.

Question 21

Formulae and changing the subject2 marksGrade 4CalculatorOn both tiers
Rearrange a linear formula to make a the subject.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 21.

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Answera=p+93a = \frac{p + 9}{3}2 marks

Worked solution Checked against the mark scheme

p=3a−9p = 3a - 9

Add 9: p+9=3ap + 9 = 3a

Divide by 3: a=p+93a = \frac{p + 9}{3}

Watch out: Writing a=p+9÷3a = p + 9 \div 3 without brackets.

Question 22

Sharing in a ratio1 markGrade 3CalculatorOn both tiers
Explain the mistake in a worked attempt to share an amount in a ratio.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 22.

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AnswerHe should add the parts (3 + 5 = 8) and divide 120 by 8, not by 3 and by 51 mark

Worked solution Checked against the mark scheme

The ratio 3 : 5 has 3+5=83 + 5 = 8 parts.

One part =120÷8=15= 120 \div 8 = 15, giving 4545 and 7575.

Rob divided by 3 and by 5 separately instead of by 8.

Watch out: Just giving the correct answer (45 : 75) without saying what went wrong.

Question 23

Charts, graphs and time series3 marksGrade 4CalculatorOn both tiers
Use given totals to work out how many boys chose a particular language.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 23.

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Answer223 marks

Worked solution Checked against the mark scheme

German: 200−104−70=26200 - 104 - 70 = 26, so boys choosing German =26−18=8= 26 - 18 = 8

Boys: 90, of which 60 chose French and 8 chose German.

Boys choosing Spanish =90−60−8=22= 90 - 60 - 8 = 22

Watch out: Forgetting to subtract the girls who chose German from the German total.

Question 24

Volume and surface area4 marksGrade 5CalculatorOn both tiers
Find the volume of four cylindrical tanks and check whether there is enough fertiliser for a 1 : 100 mix.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 24.

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AnswerYes: about 31.85 litres of fertiliser are needed and she has 324 marks

Worked solution Checked against the mark scheme

One tank: π×402×160≈804 248 cm3\pi \times 40^2 \times 160 \approx 804\,248\text{ cm}^3

Four tanks: ≈3 216 991 cm3≈3217\approx 3\,216\,991\text{ cm}^3 \approx 3217 litres

Fertiliser is 1 part in 101: 3217÷101≈31.853217 \div 101 \approx 31.85 litres

31.85<3231.85 < 32, so yes, she has enough.

Watch out: Dividing by 100 instead of 101, or using the diameter as the radius.

Question 25

Similar shapes4 marksGrade 5CalculatorOn both tiers
Use a scale factor between similar triangles to find two missing lengths.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 25.

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(a)16 cm2 marks
(b)5.5 cm2 marks

Worked solution Checked against the mark scheme

AC = 5 matches DF = 20, so the scale factor is 20÷5=420 \div 5 = 4.

(a) EF matches BC: 4×4=164 \times 4 = 16 cm

(b) AB matches DE: 22÷4=5.522 \div 4 = 5.5 cm

Watch out: Matching the wrong sides, e.g. pairing 5 cm with 22 cm.

Question 26

Tree diagrams and combined events4 marksGrade 4CalculatorOn both tiers
Fill in the missing branches of a tree diagram for two independent events and find the chance both happen.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 26.

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(a)0.7 on the first branch; 0.65 on both second 'do not win' branches2 marks
(b)0.1052 marks

Worked solution Checked against the mark scheme

(a) Not winning the sports quiz: 1−0.3=0.71 - 0.3 = 0.7. Not winning the music quiz: 1−0.35=0.651 - 0.35 = 0.65 on both pairs of branches.

(b) P(both)=0.3×0.35=0.105P(\text{both}) = 0.3 \times 0.35 = 0.105

Watch out: Adding the probabilities (0.65) instead of multiplying.

Question 27

Units and converting units4 marksGrade 5CalculatorOn both tiers
Convert a volume from cm³ to m³ and a speed from km/h to m/s.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 27.

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(a)0.008 m³1 mark
(b)50 m/s3 marks

Worked solution Checked against the mark scheme

(a) 1 m3=1003=1 000 000 cm31\text{ m}^3 = 100^3 = 1\,000\,000\text{ cm}^3, so 8000÷1 000 000=0.008 m38000 \div 1\,000\,000 = 0.008\text{ m}^3

(b) 180180 km =180 000= 180\,000 m, and 1 hour =3600= 3600 s

180 000÷3600=50180\,000 \div 3600 = 50 m/s

Watch out: Dividing by 100 in (a) instead of by 1 000 000.

Question 28

Averages and spread3 marksGrade 5CalculatorOn both tiers
Use an overall mean and one group's mean to find the mean of the other group.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 28.

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Answer158 cm3 marks

Worked solution Checked against the mark scheme

Total for everyone: 50×167.6=838050 \times 167.6 = 8380 cm

Total for men: 20×182=364020 \times 182 = 3640 cm

Women: (8380−3640)÷30=4740÷30=158(8380 - 3640) \div 30 = 4740 \div 30 = 158 cm

Watch out: Averaging the two means, e.g. working out 2×167.6−1822 \times 167.6 - 182.

Question 29

Standard form3 marksGrade 5CalculatorOn both tiers
Convert standard form to an ordinary number and evaluate a calculation in standard form.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 29.

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(a)0.0006751 mark
(b)6.592×1056.592 \times 10^52 marks

Worked solution Checked against the mark scheme

(a) Move the decimal point 4 places left: 0.000675

(b) 2.56×106×4.12×10−3=10 547.22.56 \times 10^6 \times 4.12 \times 10^{-3} = 10\,547.2

10 547.2÷(1.6×10−2)=659 200=6.592×10510\,547.2 \div (1.6 \times 10^{-2}) = 659\,200 = 6.592 \times 10^5

Watch out: Leaving the answer as 659 200 or as 65.92×10465.92 \times 10^4.

Question 30

Vectors4 marksGrade 5Calculator
Add and subtract column vectors, and draw a multiple of a vector on a grid.

© Pearson Education Ltd. November 2022 Paper 3 (Foundation, calculator), question 30.

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(a(i))(15)\begin{pmatrix}1\\5\end{pmatrix}1 mark
(a(ii))(05)\begin{pmatrix}0\\5\end{pmatrix}2 marks
(b)A line from P, 6 right and 4 down1 mark

Worked solution Checked against the mark scheme

(a)(i) (23)+(−12)=(15)\begin{pmatrix}2\\3\end{pmatrix} + \begin{pmatrix}-1\\2\end{pmatrix} = \begin{pmatrix}1\\5\end{pmatrix}

(ii) 2a=(46)2\mathbf{a} = \begin{pmatrix}4\\6\end{pmatrix}, so 2a−c=(4−46−1)=(05)2\mathbf{a} - \mathbf{c} = \begin{pmatrix}4-4\\6-1\end{pmatrix} = \begin{pmatrix}0\\5\end{pmatrix}

(b) d\mathbf{d} goes 3 right and 2 down, so 2d2\mathbf{d} goes 6 right and 4 down from P.

Watch out: Forgetting to double both components of a in (ii).

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