Edexcel GCSE Maths · 1MA1

November 2021 Paper 3 Foundation

Calculator · 28 questions · 80 marks · 1 hour 30 minutes. Try each question on paper, then press "Show answer".

Question 1

Percentages1 markGrade 1Calculator
Convert a percentage into a decimal.

© Pearson Education Ltd. November 2021 Paper 3 (Foundation, calculator), question 1.

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Answer0.451 mark

Worked solution Checked against the mark scheme

Per cent means out of 100, so divide by 100.

45÷100=0.4545 \div 100 = 0.45

Watch out: Writing 4.5 or 0.045 by moving the decimal point the wrong number of places.

Question 2

Factors, multiples and primes1 markGrade 1Calculator
Give any two numbers that divide exactly into 35.

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AnswerAny two of 1, 5, 7, 351 mark

Worked solution Checked against the mark scheme

Find pairs that multiply to 35: 1×351 \times 35 and 5×75 \times 7.

So the factors are 1, 5, 7 and 35. Any two of these will do, e.g. 5 and 7.

Watch out: Giving multiples of 35 (such as 70) instead of factors.

Question 3

Units and converting units1 markGrade 1Calculator
Find the time a given number of hours and minutes after a morning start time.

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Answer10.45 am1 mark

Worked solution Checked against the mark scheme

Add the 2 hours first: 8.05 am → 10.05 am.

Then add 40 minutes: 10.05 am → 10.45 am.

Watch out: Treating time as decimal and getting a wrong carry, e.g. 10.85.

Question 4

Fractions1 markGrade 1Calculator
Find a unit fraction of a whole number.

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Answer111 mark

Worked solution Checked against the mark scheme

To find 16\frac{1}{6} of an amount, divide by 6.

66÷6=1166 \div 6 = 11

Watch out: Multiplying by 6 instead of dividing.

Question 5

Bearings and scale drawings1 markGrade 1Calculator
Mark the point halfway along a given line segment.

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AnswerA cross at the midpoint of AB1 mark

Worked solution Checked against the mark scheme

Measure the length of AB with a ruler.

Halve that length, measure that far from A along the line, and mark a cross there.

Watch out: Estimating by eye instead of measuring.

Question 6

Simplify a product of letters and a number, then collect like terms in an expression.

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(a)4ab4ab1 mark
(b)3x+83x + 82 marks

Worked solution Checked against the mark scheme

(a) Write the number first and drop the multiplication signs: 4ab4ab.

(b) Collect the xx terms: 4x−x=3x4x - x = 3x.

Collect the numbers: 3+5=83 + 5 = 8.

So the answer is 3x+83x + 8.

Watch out: In (b), treating −x-x as −1-1 or getting 5x5x by adding instead of subtracting.

Question 7

Listing outcomes and sample spaces2 marksGrade 2Calculator
List every possible pair when one card is taken from each of two bags.

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AnswerEJ, EK, FJ, FK, GJ, GK2 marks

Worked solution Checked against the mark scheme

Work systematically: take each letter from bag A in turn and pair it with each letter from bag B.

E: EJ, EK

F: FJ, FK

G: GJ, GK

That gives 3×2=63 \times 2 = 6 outcomes.

Watch out: Missing an outcome or listing the same pair twice.

Question 8

Show that the total of several ticket and hotel costs is more than a given amount.

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AnswerTotal is 2540 dollars, which is more than 25003 marks

Worked solution Checked against the mark scheme

Planes: 2×600=12002 \times 600 = 1200

Hotel: 7×120=8407 \times 120 = 840

Theme park: 2×250=5002 \times 250 = 500

Total: 1200+840+500=25401200 + 840 + 500 = 2540 dollars, and 2540>25002540 > 2500.

Watch out: Forgetting to multiply the hotel cost by the number of nights.

Question 9

Charts, graphs and time series3 marksGrade 2Calculator
Complete a two-way table of colour and material from given facts.

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AnswerPlastic: 4, 5, 23, 32; Not plastic: 8, 9, 7, 24; Totals: 12, 14, 30, 563 marks

Worked solution Checked against the mark scheme

Put in the given values: total 56, plastic total 32, blue total 14, blue plastic 5, red not plastic 8, red total 12.

Red plastic: 12−8=412 - 8 = 4. Blue not plastic: 14−5=914 - 5 = 9.

Black total: 56−12−14=3056 - 12 - 14 = 30. Black plastic: 32−4−5=2332 - 4 - 5 = 23.

Black not plastic: 30−23=730 - 23 = 7. Not plastic total: 56−32=2456 - 32 = 24.

Watch out: Putting the given numbers in the wrong row, e.g. writing 8 as red plastic.

Question 10

Find how many items of a given price can be bought with a fixed budget.

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Answer613 marks

Worked solution Checked against the mark scheme

300÷4.85=61.85...300 \div 4.85 = 61.85...

She cannot buy part of a book, and 62 books would cost more than £300, so round down.

She can buy 61 books.

Watch out: Rounding 61.85 up to 62.

Question 11

Units and converting units3 marksGrade 2Calculator
Convert minutes into hours and minutes, then write an expression for average speed.

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(a)3 hours 16 minutes2 marks
(b)x2\frac{x}{2}1 mark

Worked solution Checked against the mark scheme

(a) 3×60=1803 \times 60 = 180 minutes, and 196−180=16196 - 180 = 16.

So 196 minutes is 3 hours 16 minutes.

(b) Speed = distance ÷ time, so the speed is x2\frac{x}{2} miles per hour.

Watch out: In (a), writing 3.26 hours as 3 hours 26 minutes.

Question 12

Measure a map distance and use a scale to find the real distance, then use a ratio scale to convert a drawing length to metres.

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(a)50 km2 marks
(b)60 m2 marks

Worked solution Checked against the mark scheme

(a) Measure the distance on the map: about 2.5 cm.

2.5×20=502.5 \times 20 = 50 km

(b) 5×1200=60005 \times 1200 = 6000 cm on the ground.

6000÷100=606000 \div 100 = 60 m

Watch out: In (b), giving 6000 without converting centimetres to metres.

Question 13

Ratio4 marksGrade 3Calculator
Turn a land-to-water ratio into a percentage, then turn a percentage into a land-to-water ratio.

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(a)40%2 marks
(b)20 : 802 marks

Worked solution Checked against the mark scheme

(a) There are 2+3=52 + 3 = 5 parts, and land is 2 of them.

25×100=40%\frac{2}{5} \times 100 = 40\%

(b) Water is 100−20=80%100 - 20 = 80\%.

Land : water =20:80=1:4= 20 : 80 = 1 : 4

Watch out: In (a), using 23\frac{2}{3} instead of 25\frac{2}{5}.

Question 14

Fractions3 marksGrade 3Calculator
Find the remaining part of a cost after a given fraction has been spent.

© Pearson Education Ltd. November 2021 Paper 3 (Foundation, calculator), question 14.

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Answer£80 million3 marks

Worked solution Checked against the mark scheme

The land is 1−1315=2151 - \frac{13}{15} = \frac{2}{15} of the cost.

600÷15=40600 \div 15 = 40

40×2=8040 \times 2 = 80, so the land cost £80 million.

Watch out: Giving the building cost (£520 million) instead of the land cost.

Question 15

Angle facts and parallel lines1 markGrade 2Calculator
Explain why a set of angle measurements around a point is impossible.

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AnswerThe angles only add up to 260°, but angles around a point add up to 360°1 mark

Worked solution Checked against the mark scheme

Add the angles: 23+145+23+69=260°23 + 145 + 23 + 69 = 260°.

Angles around a point must add up to 360°360°, so these results cannot be right.

Watch out: Just stating the total (260°) without saying it should be 360°.

Question 16

Transformations2 marksGrade 4Calculator
Describe the single transformation that takes a small triangle onto a larger one on a grid.

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AnswerEnlargement, scale factor 4, centre (1, 1)2 marks

Worked solution Checked against the mark scheme

The shape keeps the same angles but gets bigger, so it is an enlargement.

AB is 1 unit and AD is 4 units, so the scale factor is 4.

Point A stays still at (1,1)(1, 1), so that is the centre.

Enlargement, scale factor 4, centre (1,1)(1, 1).

Watch out: Leaving out the centre of enlargement, or mentioning a second transformation.

Question 17

Expanding brackets and simplifying7 marksGrade 3Calculator
Expand a bracket, factorise an expression, solve a linear equation with a bracket, and simplify a product using index laws.

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(a)y2+5yy^2 + 5y1 mark
(b)2(2a−3)2(2a - 3)1 mark
(c)x=2.9x = 2.93 marks
(d)20e3f420e^3f^42 marks

Worked solution Checked against the mark scheme

(a) y×y+y×5=y2+5yy \times y + y \times 5 = y^2 + 5y

(b) The highest common factor of 4 and 6 is 2: 2(2a−3)2(2a - 3)

(c) 10x−8=2110x - 8 = 21, so 10x=2910x = 29 and x=2.9x = 2.9

(d) 4×5=204 \times 5 = 20, e2×e=e3e^2 \times e = e^3, f×f3=f4f \times f^3 = f^4, giving 20e3f420e^3f^4

Watch out: In (d), multiplying the powers instead of adding them, e.g. e2e^2.

Question 18

Units and converting units1 markGrade 4Calculator
Convert one square metre into square centimetres.

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Answer10 000 cm²1 mark

Worked solution Checked against the mark scheme

1 m = 100 cm, so a 1 m by 1 m square is 100 cm by 100 cm.

100×100=10 000100 \times 100 = 10\,000 cm²

Watch out: Giving 100, forgetting that area uses two dimensions.

Question 19

Area and perimeter4 marksGrade 5Calculator
Find the area of a tilted square drawn inside a larger square.

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Answer34 cm²4 marks

Worked solution Checked against the mark scheme

The big square has side 3+5=83 + 5 = 8 cm, so its area is 6464 cm².

Each corner triangle has area 12×3×5=7.5\frac{1}{2} \times 3 \times 5 = 7.5 cm².

Shaded area =64−4×7.5=34= 64 - 4 \times 7.5 = 34 cm².

(Or: side2=32+52=34^2 = 3^2 + 5^2 = 34.)

Watch out: Taking the shaded side as 5 cm or 8 cm and squaring it.

Question 20

Charts, graphs and time series3 marksGrade 3Calculator
Draw an ordered stem-and-leaf diagram with a key for 15 heights.

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Answer1 | 5 7 8 9 9; 2 | 0 2 2 4 5 5 8; 3 | 2 3 5 with key e.g. 2 | 5 means 25 cm3 marks

Worked solution Checked against the mark scheme

Use the tens digit as the stem and the units digit as the leaf.

Put the leaves in order:

1 | 5 7 8 9 9

2 | 0 2 2 4 5 5 8

3 | 2 3 5

Key: 2 | 5 means 25 cm. Check there are 15 leaves.

Watch out: Forgetting the key or leaving the leaves unordered.

Question 21

Scatter graphs and correlation4 marksGrade 3CalculatorOn both tiers
Identify an outlier on a scatter graph, estimate a value, and comment on a claim about correlation.

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(a)(100, 18)1 mark
(b)About 13.8 mg/m³ (12.8 to 14.8)2 marks
(c)No, the rest of the points still show positive correlation1 mark

Worked solution Checked against the mark scheme

(a) The point far from the others is at (100,18)(100, 18).

(b) Draw a line of best fit through the main trend and read up from 370: about 13.8 mg/m³.

(c) No. One outlier does not remove the pattern; the other points still show positive correlation.

Watch out: In (c), agreeing with Alfie or saying 'yes'.

Question 22

Sharing in a ratio4 marksGrade 4CalculatorOn both tiers
Work out the cost of cheese needed for a recipe split in a three-part ratio, given a price per pack weight.

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Answer£12.86 (or £13.50 if whole packs are bought)4 marks

Worked solution Checked against the mark scheme

Total parts: 9+2+1=129 + 2 + 1 = 12

Cheese: 6000÷12×2=10006000 \div 12 \times 2 = 1000 g

1000÷175=5.714...1000 \div 175 = 5.714... lots of 175 g

5.714...×2.25=£12.857...5.714... \times 2.25 = £12.857..., so about £12.86

Watch out: Using 2 out of 3 parts instead of 2 out of 12.

Question 23

Standard form4 marksGrade 4CalculatorOn both tiers
Convert between standard form and ordinary numbers, then add two numbers in standard form.

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(a)450 0001 mark
(b)7×10−37 \times 10^{-3}1 mark
(c)4.73×1034.73 \times 10^32 marks

Worked solution Checked against the mark scheme

(a) Move the digits 5 places: 4.5×105=450 0004.5 \times 10^5 = 450\,000

(b) 0.007=7×10−30.007 = 7 \times 10^{-3}

(c) 4200+530=4730=4.73×1034200 + 530 = 4730 = 4.73 \times 10^3

Watch out: In (c), adding the numbers and powers separately to get 9.5×1059.5 \times 10^5.

Question 24

Speed, density and pressure4 marksGrade 5CalculatorOn both tiers
Compare how long two suppliers take to fill a tank using different rates and units, and find the time difference.

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Answer260 minutes4 marks

Worked solution Checked against the mark scheme

Company A: 1 min 40 s =53= \frac{5}{3} min, so the rate is 8÷53=4.88 \div \frac{5}{3} = 4.8 litres per minute.

Time A =2400÷4.8=500= 2400 \div 4.8 = 500 min.

Company B: 2.2×4.54=9.9882.2 \times 4.54 = 9.988 litres per minute.

Time B =2400÷9.988=240.29= 2400 \div 9.988 = 240.29 min.

Difference =500−240.29=259.7= 500 - 240.29 = 259.7, about 260 minutes.

Watch out: Treating 1 minute 40 seconds as 1.4 minutes.

Question 25

Sequences and the nth term3 marksGrade 4CalculatorOn both tiers
Find the fifth term of an algebraic Fibonacci-type sequence and use the total of five terms to find the unknown.

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Answer123 marks

Worked solution Checked against the mark scheme

Each term is the sum of the two before, so the fifth term is 3a+5a=8a3a + 5a = 8a.

a+2a+3a+5a+8a=19aa + 2a + 3a + 5a + 8a = 19a

19a=22819a = 228, so a=12a = 12.

Watch out: Summing only the four given terms, giving 11a=22811a = 228.

Question 26

Probability scale and basic probability4 marksGrade 4CalculatorOn both tiers
Find two missing probabilities from their sum and difference, then use one probability to find the total number of counters.

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(a)green 0.5, pink 0.32 marks
(b)1202 marks

Worked solution Checked against the mark scheme

(a) The probabilities add to 1: 1−0.05−0.15=0.81 - 0.05 - 0.15 = 0.8 for green and pink together.

Green is 0.2 more than pink: 2p+0.2=0.82p + 0.2 = 0.8, so pink =0.3= 0.3 and green =0.5= 0.5.

(b) 0.150.15 of the counters are blue: 18÷0.15=12018 \div 0.15 = 120.

Watch out: In (a), splitting 0.8 equally as 0.4 and 0.4.

Question 27

Arcs and sectors4 marksGrade 5CalculatorOn both tiers
Find the area of a segment cut off a quarter circle by a chord.

© Pearson Education Ltd. November 2021 Paper 3 (Foundation, calculator), question 27.

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Answer18.3 cm²4 marks

Worked solution Checked against the mark scheme

Quarter circle: 14×π×82=50.265...\frac{1}{4} \times \pi \times 8^2 = 50.265... cm²

Triangle OPROPR: 12×8×8=32\frac{1}{2} \times 8 \times 8 = 32 cm²

Segment =50.265...−32=18.265...= 50.265... - 32 = 18.265...

So the area is 18.318.3 cm² (3 s.f.).

Watch out: Using 2πr2\pi r (circumference) instead of πr2\pi r^2.

Question 28

Sketch the reciprocal graph on a set of axes.

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AnswerTwo curves, one in the first quadrant and one in the third, each approaching both axes without touching2 marks

Worked solution Checked against the mark scheme

For positive xx, yy is positive and gets smaller as xx grows, so draw a curve in the top-right quadrant.

For negative xx, yy is negative, so draw the matching curve in the bottom-left quadrant.

The curves get close to the axes but never touch them, and there is no point at x=0x = 0.

Watch out: Drawing a straight line, or letting the curves cross the axes.

Finished the paper?

Add up your marks for all three papers and see what grade that would have been.