Edexcel GCSE Maths · 1MA1

June 2022 Paper 1 Foundation

Non-calculator · 30 questions · 80 marks · 1 hour 30 minutes. Try each question on paper, then press "Show answer".

Question 1

Units and converting units1 markGrade 1No calculator
Convert a length given in centimetres to millimetres.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 1.

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Answer4001 mark

Worked solution Checked against the mark scheme

There are 10 mm in 1 cm.

40×10=40040 \times 10 = 400 mm

Watch out: Dividing by 10 to get 4.

Question 2

Collect four identical letter terms into a single term.

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Answer4e4e1 mark

Worked solution Checked against the mark scheme

Adding the same term four times gives four lots of it: e+e+e+e=4ee+e+e+e = 4e

Watch out: Writing e4e^4, which means multiplying, not adding.

Question 3

Transformations1 markGrade 1No calculator
Reflect a shaded triangle on a grid in a given mirror line.

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AnswerCorrect reflection drawn1 mark

Worked solution Checked against the mark scheme

Take each corner of the triangle in turn.

Count how many squares it is from the mirror line, then plot the new corner the same distance on the other side.

Join the new corners to make the image.

Watch out: Translating the triangle across instead of flipping it.

Question 4

State the place value of one digit in a five-digit whole number.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 4.

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Answer60001 mark

Worked solution Checked against the mark scheme

16 007 has 1 ten-thousand, 6 thousands, 0 hundreds, 0 tens and 7 ones.

So the 6 is worth 60006000.

Watch out: Writing just 6, the digit, instead of the value it stands for.

Question 5

Order a fraction, a decimal and a percentage from smallest to largest.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 5.

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Answer45%, 12\frac{1}{2}, 0.551 mark

Worked solution Checked against the mark scheme

Write each as a decimal: 12=0.5\frac{1}{2} = 0.5, 0.550.55, 45%=0.4545\% = 0.45

Smallest to largest: 0.45,0.5,0.550.45, 0.5, 0.55

So: 45%, 12\frac{1}{2}, 0.55

Watch out: Thinking 45% is bigger than 0.55 because 45 > 0.55.

Question 6

Charts, graphs and time series1 markGrade 1No calculator
Read a pictogram using its key to find a total number of hours.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 6.

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Answer81 mark

Worked solution Checked against the mark scheme

Saturday has 4 symbols and each symbol stands for 2 hours.

4×2=84 \times 2 = 8 hours

Watch out: Counting the symbols (4) and forgetting the key.

Question 7

Use the money paid and the change received to find how many items of a set price were bought.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 7.

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Answer73 marks

Worked solution Checked against the mark scheme

Amount spent: 20−6=1420 - 6 = 14 pounds

Each candle costs £2: 14÷2=714 \div 2 = 7

Simon buys 7 candles.

Watch out: Dividing 20 by 2 and forgetting to take off the change.

Question 8

Charts, graphs and time series3 marksGrade 2No calculator
Add two bars to a bar chart and explain why a reading taken from the chart's scale is wrong.

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(a)Bars drawn to 35 for May and 20 for June2 marks
(b)Each square is worth 5 cm, so half a square is 2.5 cm and the bar shows 17.5 cm1 mark

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(a) Draw a bar up to 35 above May and a bar up to 20 above June, the same width as the others.

(b) The vertical scale goes up 5 cm per square, so half a square is 5÷2=2.55 \div 2 = 2.5 cm.

February's bar is at 15+2.5=17.515 + 2.5 = 17.5 cm, not 15.5 cm.

Watch out: Assuming each square is worth 1 unit.

Question 9

Sequences and the nth term2 marksGrade 1No calculator
Continue a pattern of L-shaped tile arrangements and fill in the missing numbers of squares.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 9.

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(a)L-shape with 5 squares down and 5 across sharing a corner (9 squares)1 mark
(b)9 and 111 mark

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(a) Each new pattern adds one square to each arm. Pattern 5 has arms 5 squares long, sharing the corner square: 9 squares.

(b) The numbers go up by 2 each time: 1, 3, 5, 7, 9, 11

Watch out: Drawing arms of 4 squares, copying Pattern 4.

Question 10

Find a temperature that is a given number of degrees above a negative temperature.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 10.

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Answer272 marks

Worked solution Checked against the mark scheme

Start at −15-15 and go up 42 degrees.

−15+42=27-15 + 42 = 27

Highest temperature: 27∘27^\circC

Watch out: Getting 57 by adding 15 and 42.

Question 11

Use two meter readings and a unit price in pence to work out an electricity bill without a calculator.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 11.

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Answer£73.60 (or 7360p)4 marks

Worked solution Checked against the mark scheme

Units used: 89 198−88 738=46089\,198 - 88\,738 = 460 kWh

Cost: 460×16=4600+2760=7360460 \times 16 = 4600 + 2760 = 7360p

7360p=£73.607360\text{p} = £73.60

Watch out: Leaving the answer as £7360 by forgetting to convert pence to pounds.

Question 12

Fractions4 marksGrade 3No calculator
Add two fractions with different denominators and multiply two fractions, simplifying fully.

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(a)712\frac{7}{12}2 marks
(b)316\frac{3}{16}2 marks

Worked solution Checked against the mark scheme

(a) 16=212\frac{1}{6} = \frac{2}{12}, so 512+212=712\frac{5}{12} + \frac{2}{12} = \frac{7}{12}

(b) 310×58=1580\frac{3}{10} \times \frac{5}{8} = \frac{15}{80}

Divide top and bottom by 5: 316\frac{3}{16}

Watch out: Adding the denominators in (a) to get 6/18.

Question 13

Probability scale and basic probability2 marksGrade 2No calculator
Write a simple probability and find the probability of the only other outcome.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 13.

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(a)415\frac{4}{15}1 mark
(b)0.71 mark

Worked solution Checked against the mark scheme

(a) 4 red out of 15 sweets: P(red)=415P(\text{red}) = \frac{4}{15}

(b) Probabilities add to 1: 1−0.3=0.71 - 0.3 = 0.7

Watch out: Writing the probability as a ratio, 4 : 15.

Question 14

Substitute a value into a linear formula to find y.

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Answer192 marks

Worked solution Checked against the mark scheme

y=6×4−5y = 6 \times 4 - 5

y=24−5=19y = 24 - 5 = 19

Watch out: Reading 6x as 64 when x = 4.

Question 15

Rounding and estimation3 marksGrade 3No calculator
Estimate a product by rounding, then use a given product to find a related one.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 15.

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(a)180 (from 90×290 \times 2)2 marks
(b)947.21 mark

Worked solution Checked against the mark scheme

(a) Round each number: 92≈9092 \approx 90 and 1.63≈21.63 \approx 2

90×2=18090 \times 2 = 180

(b) 29.629.6 is 2.96×102.96 \times 10 and 3232 is 3.2×103.2 \times 10, so the answer is 9.472×100=947.29.472 \times 100 = 947.2

Watch out: Working out the exact answer (149.96) instead of estimating.

Question 16

Speed, density and pressure4 marksGrade 3No calculator
Use distance and average speed to find an arrival time, then say how a faster speed changes it.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 16.

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(a)08 453 marks
(b)He will arrive earlier1 mark

Worked solution Checked against the mark scheme

(a) Time =50÷40=1.25= 50 \div 40 = 1.25 hours

0.25×60=150.25 \times 60 = 15, so 1 hour 15 minutes.

07 30 + 1 h 15 min = 08 45

(b) Going faster over the same distance takes less time, so he arrives earlier.

Watch out: Treating 1.25 hours as 1 hour 25 minutes, giving 08 55.

Question 17

Tree diagrams and combined events5 marksGrade 3No calculator
Complete a frequency tree from given totals and find a probability from it.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 17.

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(a)Adult 32 (passed 20, failed 12); child 40 (passed 34, failed 6)3 marks
(b)1272\frac{12}{72}2 marks

Worked solution Checked against the mark scheme

(a) Adults: 32, so children: 72−32=4072 - 32 = 40

Adults failed: 32−20=1232 - 20 = 12

Children passed: 40−6=3440 - 6 = 34

(b) 12 adults failed out of 72 people: 1272=16\frac{12}{72} = \frac{1}{6}

Watch out: Giving 12/32 by using only the adults as the total.

Question 18

Direct and inverse proportion2 marksGrade 2No calculator
Scale up one ingredient of a recipe for a larger number of items.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 18.

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Answer1002 marks

Worked solution Checked against the mark scheme

25 scones is 25÷10=2.525 \div 10 = 2.5 times the recipe.

40×2.5=10040 \times 2.5 = 100 g of sugar

Watch out: Adding 15 g because 25 is 15 more than 10.

Question 19

Increase an amount by a percentage without a calculator.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 19.

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Answer2883 marks

Worked solution Checked against the mark scheme

10%10\% of 240 is 24, so 20%20\% is 4848

240+48=288240 + 48 = 288

Watch out: Giving just 48, the increase, as the answer.

Question 20

Fractions3 marksGrade 5No calculator
Use the shaded fractions of two identical rectangles to find the shaded fraction of a third.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 20.

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Answer3988\frac{39}{88}3 marks

Worked solution Checked against the mark scheme

The top strip of B matches the unshaded part of A: 1−58=381 - \frac{5}{8} = \frac{3}{8}

The bottom strip of B matches the unshaded part of C: 1−911=2111 - \frac{9}{11} = \frac{2}{11}

Shaded part of B: 1−38−211=88−33−1688=39881 - \frac{3}{8} - \frac{2}{11} = \frac{88 - 33 - 16}{88} = \frac{39}{88}

Watch out: Subtracting 5/8 from 9/11 without thinking about which strips match.

Question 21

Charts, graphs and time series3 marksGrade 3No calculator
Draw an ordered stem and leaf diagram with a key for a list of ages.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 21.

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Answer1 | 7 9; 2 | 5 5 6 7 7 7 8 9; 3 | 3 7 7; 4 | 5 7, with key such as 2 | 5 = 25 years3 marks

Worked solution Checked against the mark scheme

Use the tens digit as the stem and the units digit as the leaf, then put the leaves in order:

1 | 7 9

2 | 5 5 6 7 7 7 8 9

3 | 3 7 7

4 | 5 7

Key: 2 | 5 means 25 years

Watch out: Forgetting the key or leaving the leaves unordered.

Question 22

Volume and surface area3 marksGrade 5No calculator
Read a cylinder's radius and height from a plan and front elevation, then find its volume in terms of pi.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 22.

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Answer45π45\pi3 marks

Worked solution Checked against the mark scheme

The plan is a circle 6 cm across, so the radius is 3 cm.

The front elevation is 5 cm tall, so the height is 5 cm.

V=πr2h=π×32×5=45πV = \pi r^2 h = \pi \times 3^2 \times 5 = 45\pi cm³

Watch out: Using the diameter 6 as the radius, giving 180π.

Question 23

Inequalities2 marksGrade 4No calculatorOn both tiers
Solve a two-step linear inequality.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 23.

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Answerx<5x < 52 marks

Worked solution Checked against the mark scheme

7x−27<87x - 27 < 8

Add 27: 7x<357x < 35

Divide by 7: x<5x < 5

Watch out: Writing x = 5 instead of an inequality.

Question 24

Factors, multiples and primes2 marksGrade 4No calculatorOn both tiers
Write a number as a product of its prime factors.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 24.

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Answer2×2×312 \times 2 \times 312 marks

Worked solution Checked against the mark scheme

124=2×62124 = 2 \times 62

62=2×3162 = 2 \times 31, and 31 is prime.

So 124=2×2×31=22×31124 = 2 \times 2 \times 31 = 2^2 \times 31

Watch out: Stopping at 2 × 62 or 4 × 31.

Question 25

Ratio5 marksGrade 5No calculatorOn both tiers
Share a total in a ratio, then take a fraction and a percentage away to find the remaining group.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 25.

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Answer305 marks

Worked solution Checked against the mark scheme

Cars: 160÷10=16160 \div 10 = 16, 16×3=4816 \times 3 = 48

Electric: 48÷8=648 \div 8 = 6

Diesel: 25%25\% of 48 =12= 12

Petrol: 48−6−12=3048 - 6 - 12 = 30

Watch out: Using all 160 vehicles instead of just the 48 cars (giving 100).

Question 26

Standard form4 marksGrade 5No calculatorOn both tiers
Convert between standard form and ordinary numbers and multiply two numbers in standard form.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 26.

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(a)0.001631 mark
(b)4.38×1054.38 \times 10^51 mark
(c)2.4×10−12.4 \times 10^{-1}2 marks

Worked solution Checked against the mark scheme

(a) Move the decimal point 3 places left: 0.001630.00163

(b) 438 000=4.38×100 000=4.38×105438\,000 = 4.38 \times 100\,000 = 4.38 \times 10^5

(c) 4×6=244 \times 6 = 24 and 103×10−5=10−210^3 \times 10^{-5} = 10^{-2}

24×10−2=2.4×10−124 \times 10^{-2} = 2.4 \times 10^{-1}

Watch out: Leaving (c) as 24 × 10⁻², which is not in standard form.

Question 27

Angles in polygons3 marksGrade 5No calculatorOn both tiers
Find the angle between a regular hexagon and a regular pentagon that share a side.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 27.

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Answer1323 marks

Worked solution Checked against the mark scheme

Hexagon interior angle: 180−360÷6=120∘180 - 360 \div 6 = 120^\circ

Pentagon interior angle: 180−360÷5=108∘180 - 360 \div 5 = 108^\circ

Angles round a point add to 360∘360^\circ: x=360−120−108=132∘x = 360 - 120 - 108 = 132^\circ

Watch out: Using exterior angles in place of interior ones and getting 228.

Question 28

Quadratic graphs6 marksGrade 5No calculatorOn both tiers
Complete a table of values for a quadratic, plot its graph, and read off where it crosses the x-axis.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 28.

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(a)5, −1, 1, 5 (for x = −1, 2, 3, 4)2 marks
(b)Smooth U-shaped curve through the plotted points2 marks
(c)x≈0.4x \approx 0.4 and x≈2.6x \approx 2.62 marks

Worked solution Checked against the mark scheme

(a) x=−1x = -1: 1+3+1=51 + 3 + 1 = 5; x=2x = 2: 4−6+1=−14 - 6 + 1 = -1; x=3x = 3: 9−9+1=19 - 9 + 1 = 1; x=4x = 4: 16−12+1=516 - 12 + 1 = 5

(b) Plot (−1,5),(0,1),(1,−1),(2,−1),(3,1),(4,5)(-1,5), (0,1), (1,-1), (2,-1), (3,1), (4,5) and join with a smooth curve.

(c) The curve crosses y=0y = 0 at about x=0.4x = 0.4 and x=2.6x = 2.6

Watch out: Working out (−1)2(-1)^2 as −1-1, giving the wrong value at x = −1.

Question 29

Speed, density and pressure3 marksGrade 5No calculatorOn both tiers
Find the densities of two cubes from their side lengths and masses and write them as a simplified ratio.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 29.

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Answer3 : 23 marks

Worked solution Checked against the mark scheme

Volumes: 33=273^3 = 27 cm³ and 43=644^3 = 64 cm³

Densities: 81÷27=381 \div 27 = 3 g/cm³ and 128÷64=2128 \div 64 = 2 g/cm³

Ratio: 3:23 : 2

Watch out: Using side length times 6 or squaring instead of cubing.

Question 30

Pythagoras and trigonometry1 markGrade 5No calculator
Recall the exact value of the sine of 30 degrees.

© Pearson Education Ltd. June 2022 Paper 1 (Foundation, non-calculator), question 30.

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Answer0.51 mark

Worked solution Checked against the mark scheme

This is one of the exact trig values to learn: sin⁡30∘=12=0.5\sin 30^\circ = \frac{1}{2} = 0.5

Watch out: Mixing it up with cos 30°.

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