Edexcel GCSE Maths · 1MA1

June 2023 Paper 2 Foundation

Calculator · 28 questions · 80 marks · 1 hour 30 minutes. Try each question on paper, then press "Show answer".

Question 1

Rounding and estimation1 markGrade 1Calculator
Round a four-digit whole number to the nearest 100.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 1.

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Answer62001 mark

Worked solution Checked against the mark scheme

The hundreds digit is 1 and the next digit is 8, which is 5 or more, so round up.

6184→62006184 \to 6200

Watch out: Writing 6100 by rounding down.

Question 2

Convert a one-decimal-place number into a fraction.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 2.

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Answer710\frac{7}{10}1 mark

Worked solution Checked against the mark scheme

The 7 is in the tenths column, so 0.7=7100.7 = \frac{7}{10}.

Watch out: Writing 7100\frac{7}{100} or 17\frac{1}{7}.

Question 3

Units and converting units1 markGrade 1Calculator
Convert a length from metres to centimetres.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 3.

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Answer9001 mark

Worked solution Checked against the mark scheme

There are 100 cm in 1 m, so 9×100=9009 \times 100 = 900 cm.

Watch out: Multiplying by 10 or 1000 instead of 100.

Question 4

Simplify a product of a number and an algebraic term.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 4.

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Answer12t12t1 mark

Worked solution Checked against the mark scheme

Multiply the numbers: 3×4=123 \times 4 = 12, and keep the letter.

3×4t=12t3 \times 4t = 12t

Watch out: Writing 7t7t by adding the numbers.

Question 5

Factors, multiples and primes1 markGrade 1Calculator
Pick the number from a short list that divides exactly by 25.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 5.

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Answer1001 mark

Worked solution Checked against the mark scheme

Multiples of 25 are 25, 50, 75, 100, ...

Only 100 is in the list (25×4=10025 \times 4 = 100).

Watch out: Choosing 20 or 40 because they are multiples of 5 or 10.

Question 6

Mark probabilities for rolling a 7 and for rolling an even number on a probability scale for a normal dice.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 6.

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(a)Cross at 01 mark
(b)Cross at 12\frac{1}{2}1 mark

Worked solution Checked against the mark scheme

(a) A normal dice has no 7, so rolling a 7 is impossible: probability 00.

(b) Even numbers are 2, 4 and 6, so the probability is 36=12\frac{3}{6} = \frac{1}{2}, halfway along the scale.

Watch out: Marking 'even number' at 16\frac{1}{6} or 36\frac{3}{6} at the wrong point.

Question 7

Properties of 2D shapes and symmetry3 marksGrade 2Calculator
Measure a side and an angle of a drawn triangle, then name a triangle with two equal sides.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 7.

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(a)9.3 cm (9.1 to 9.5 accepted)1 mark
(b)106∘106^\circ (104 to 108 accepted)1 mark
(c)Isosceles1 mark

Worked solution Checked against the mark scheme

(a) Put the ruler's 0 on A and read off at C: about 9.39.3 cm.

(b) Place the protractor's centre on B, line up one side with 0 and read the scale that starts at 0: about 106∘106^\circ. It is obtuse, so the answer must be over 90∘90^\circ.

(c) Two equal sides (QP=QRQP = QR) means the triangle is isosceles.

Watch out: Reading the wrong protractor scale and giving about 74∘74^\circ.

Question 8

Use a map scale to find the real distance of a journey made of two measured legs.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 8.

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Answer96 km3 marks

Worked solution Checked against the mark scheme

Total map distance: 8+16=248 + 16 = 24 cm

Each cm is 4 km: 24×4=9624 \times 4 = 96 km

Watch out: Only converting one leg of the journey, e.g. 16×4=6416 \times 4 = 64.

Question 9

Sequences and the nth term3 marksGrade 2Calculator
Give the next term of a linear sequence, then write the ratio of two of its terms in simplest form.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 9.

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(a)281 mark
(b)4:94 : 92 marks

Worked solution Checked against the mark scheme

(a) The terms go up by 5, so the next term is 23+5=2823 + 5 = 28.

(b) The second term is 8 and the fourth is 18.

8:188 : 18, divide both by 2: 4:94 : 9

Watch out: Writing the ratio the wrong way round as 9:49 : 4.

Question 10

Read a car-park charge from a straight-line cost graph, then work backwards from a charge to find when a driver left.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 10.

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(a)£61 mark
(b)14 00 (2 pm)3 marks

Worked solution Checked against the mark scheme

(a) Go up from 4 hours to the line and across: £6.

(b) Go across from £9 to the line and down: 6 hours.

08 00+608\,00 + 6 hours =14 00= 14\,00 (2 pm)

Watch out: Writing the time as 14 pm or giving just '6'.

Question 11

Averages and spread3 marksGrade 2Calculator
Use a frequency table of weights to show the total weight of people in a lift is under a limit.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 11.

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AnswerTotal is 1060 kg, which is less than 1200 kg3 marks

Worked solution Checked against the mark scheme

Multiply each weight by how many people have it:

40+100+240+350+240+90=106040 + 100 + 240 + 350 + 240 + 90 = 1060 kg

1060<12001060 < 1200, so the total is less than 1200 kg.

Watch out: Adding the weights without multiplying by the number of people.

Question 12

Transformations2 marksGrade 2Calculator
Draw the mirror line between a shape and its reflection, then explain the error in a reflection that used the wrong axis.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 12.

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(a)The diagonal mirror line exactly halfway between A and B (sloping up to the right)1 mark
(b)Alex reflected in the yy-axis instead of the xx-axis1 mark

Worked solution Checked against the mark scheme

(a) The horizontal edge of A becomes the vertical edge of B, so the mirror line is diagonal. Draw the line that is the same distance from each corner of A as from the matching corner of B.

(b) Reflecting in the xx-axis flips the shape down, so the image should be below the xx-axis (between y=−2y = -2 and y=−4y = -4). Alex flipped it across the yy-axis instead.

Watch out: In (b), just saying 'it is the wrong way round' without naming the axis.

Question 13

Fractions2 marksGrade 2Calculator
Find a whole amount given that a known number is a unit fraction of it.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 13.

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Answer8002 marks

Worked solution Checked against the mark scheme

50 is 116\frac{1}{16} of the total, so the total is 16 lots of 50.

16×50=80016 \times 50 = 800

Watch out: Dividing 50 by 16 to get 3.125.

Question 14

Volume and surface area4 marksGrade 4Calculator
Find how many small cuboid packets fit into a larger cuboid box when the sizes are in different units.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 14.

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Answer8644 marks

Worked solution Checked against the mark scheme

Change the packet to cm: 8 cm by 6 cm by 2 cm.

Along each edge: 72÷8=972 \div 8 = 9, 48÷6=848 \div 6 = 8, 24÷2=1224 \div 2 = 12

9×8×12=8649 \times 8 \times 12 = 864

(Check: 82944÷96=86482944 \div 96 = 864.)

Watch out: Not converting mm to cm, or mixing units in the division.

Question 15

Compare the probability of a low score on a dice with a high score on an eight-sided spinner.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 15.

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AnswerThe spinner: 38=0.375\frac{3}{8} = 0.375 is greater than 26≈0.333\frac{2}{6} \approx 0.3333 marks

Worked solution Checked against the mark scheme

Dice, less than 3: scores 1 and 2, so 26=824\frac{2}{6} = \frac{8}{24}

Spinner, greater than 5: 6, 7 and 8, so 38=924\frac{3}{8} = \frac{9}{24}

924>824\frac{9}{24} > \frac{8}{24}, so the spinner is more likely.

Watch out: Counting 3 as less than 3, or 5 as greater than 5.

Question 16

Speed, density and pressure3 marksGrade 3Calculator
Work out a distance from an average speed and a time in hours and minutes.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 16.

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Answer98 km3 marks

Worked solution Checked against the mark scheme

45 minutes =4560=0.75= \frac{45}{60} = 0.75 hours, so the time is 1.751.75 hours.

Distance = speed × time =56×1.75=98= 56 \times 1.75 = 98 km

Watch out: Using 1.45 hours for 1 hour 45 minutes.

Question 17

Averages and spread4 marksGrade 3Calculator
Find a missing value from a mean and the other values.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 17.

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Answer5404 marks

Worked solution Checked against the mark scheme

Total seats =3×380=1140= 3 \times 380 = 1140

A and B together: 350+250=600350 + 250 = 600

Cinema C: 1140−600=5401140 - 600 = 540

Watch out: Dividing by 3 again or averaging the two known values.

Question 18

Direct and inverse proportion6 marksGrade 3Calculator
Find the cost of buying cans in packs, then the cost of 100 ml of a drink bought in a box.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 18.

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(a)£453 marks
(b)9p3 marks

Worked solution Checked against the mark scheme

(a) Packs: 180÷12=15180 \div 12 = 15. Cost: 15×£3=£4515 \times £3 = £45

(b) Total volume: 24×330=792024 \times 330 = 7920 ml

Cost of 1 ml: 700÷7920=0.0884700 \div 7920 = 0.0884p, so 100 ml costs 8.848.84p

To the nearest penny: 9p

Watch out: In (a), multiplying 180 by £3.

Question 19

Tree diagrams and combined events5 marksGrade 3Calculator
Complete a frequency tree about car and bicycle ownership, then find a percentage from it.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 19.

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(a)Car 150 (bicycle 45, no bicycle 105); no car 90 (bicycle 65, no bicycle 25)3 marks
(b)30%2 marks

Worked solution Checked against the mark scheme

(a) No car: 240−150=90240 - 150 = 90. Of these, 65 have a bicycle, so 90−65=2590 - 65 = 25 do not.

Car owners with a bicycle: 110−65=45110 - 65 = 45; without: 150−45=105150 - 45 = 105.

(b) 45150×100=30%\frac{45}{150} \times 100 = 30\%

Watch out: Putting 110 on the 'car and bicycle' branch.

Question 20

Calculating with integers, decimals and negatives3 marksGrade 3CalculatorOn both tiers
Evaluate a fraction containing a square root and a square on a calculator, and find a reciprocal of a decimal.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 20.

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(a)1.765279230...2 marks
(b)1.61 mark

Worked solution Checked against the mark scheme

(a) Top: 25−43.87=18.3765...25 - \sqrt{43.87} = 18.3765...

Bottom: 6+2.12=10.416 + 2.1^2 = 10.41

18.3765...÷10.41=1.765279230...18.3765... \div 10.41 = 1.765279230...

(b) Reciprocal =1÷0.625=1.6= 1 \div 0.625 = 1.6

Watch out: Typing it without brackets so only part of the top is divided.

Question 21

Factors, multiples and primes2 marksGrade 3CalculatorOn both tiers
Write a two-digit number as a product of prime factors.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 21.

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Answer2×2×3×52 \times 2 \times 3 \times 52 marks

Worked solution Checked against the mark scheme

60=2×30=2×2×15=2×2×3×560 = 2 \times 30 = 2 \times 2 \times 15 = 2 \times 2 \times 3 \times 5

So 60=22×3×560 = 2^2 \times 3 \times 5

Watch out: Listing the factors 2, 2, 3, 5 without multiplication signs, or including 1.

Question 22

Sharing in a ratio1 markGrade 3CalculatorOn both tiers
Decide whether a claim about how many red counters there are, given a red-to-blue ratio, is correct.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 22.

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AnswerNo: red is 13\frac{1}{3} of the counters, so there are 161 mark

Worked solution Checked against the mark scheme

The ratio 1:21 : 2 has 1+2=31 + 2 = 3 parts.

48÷3=1648 \div 3 = 16, so there are 16 red and 32 blue.

Helen is wrong: 24 red would be half, which is a 1:11 : 1 ratio.

Watch out: Agreeing with Helen because 1 is half of 2.

Question 23

Inequalities6 marksGrade 4CalculatorOn both tiers
Find the greatest integer in an inequality, show another inequality on a number line and solve a linear inequality with a fraction.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 23.

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(a)41 mark
(b)Closed circle at −4-4, open circle at 11, joined by a line2 marks
(c)g<25g < 253 marks

Worked solution Checked against the mark scheme

(a) nn is less than 5, so the greatest integer is 44.

(b) Filled circle at −4-4 (it is included), empty circle at 11 (not included), and a line joining them.

(c) 25g−4<6\frac{2}{5}g - 4 < 6

25g<10\frac{2}{5}g < 10

2g<502g < 50

g<25g < 25

Watch out: In (a), giving 5 even though the sign is strict.

Question 24

Forming and solving linear equations4 marksGrade 5CalculatorOn both tiers
Form and solve an equation using the areas of a triangle and a rectangle with algebraic sides.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 24.

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Answerx=1.25x = 1.254 marks

Worked solution Checked against the mark scheme

Triangle: 12×8×6x=24x\frac{1}{2} \times 8 \times 6x = 24x

Rectangle: 5(4x−1)=20x−55(4x - 1) = 20x - 5

24x=20x−5+1024x = 20x - 5 + 10

4x=54x = 5, so x=1.25x = 1.25

(Check: triangle 30, rectangle 20.)

Watch out: Forgetting to halve for the triangle, or adding the 10 to the wrong side.

Question 25

Sharing in a ratio3 marksGrade 4CalculatorOn both tiers
Find a percentage of an amount and then share it in a given ratio to find one part.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 25.

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Answer168 kg3 marks

Worked solution Checked against the mark scheme

Paper and glass: 0.57×800=4560.57 \times 800 = 456 kg

Ratio 12:712 : 7 has 19 parts: 456÷19=24456 \div 19 = 24

Glass: 7×24=1687 \times 24 = 168 kg

Watch out: Sharing all 800 kg in the ratio instead of the 57%.

Question 26

Error intervals and bounds2 marksGrade 5CalculatorOn both tiers
Write the error interval for a number that has been rounded to one decimal place.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 26.

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Answer12.65≤d<12.7512.65 \le d < 12.752 marks

Worked solution Checked against the mark scheme

Rounding to 1 d.p. means the value is within 0.050.05 of 12.712.7.

Lower bound: 12.7−0.05=12.6512.7 - 0.05 = 12.65

Upper bound: 12.7+0.05=12.7512.7 + 0.05 = 12.75

12.65≤d<12.7512.65 \le d < 12.75

Watch out: Using 12.6 and 12.8, or 12.749 as the upper bound.

Question 27

Compound interest, growth and decay4 marksGrade 5CalculatorOn both tiers
Compare two house values after two years of compound percentage growth at different rates.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 27.

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AnswerRachel's: £164 836 compared with Tamsin's £162 2404 marks

Worked solution Checked against the mark scheme

Tamsin: 150 000×1.042=£162 240150\,000 \times 1.04^2 = £162\,240

Rachel: 160 000×1.0152=£164 836160\,000 \times 1.015^2 = £164\,836

164 836>162 240164\,836 > 162\,240, so Rachel's house is worth more.

Watch out: Using simple interest (adding the same increase twice).

Question 28

Match five sketch graphs to their equations: straight lines, a quadratic, a cubic and a reciprocal.

© Pearson Education Ltd. June 2023 Paper 2 (Foundation, calculator), question 28.

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Answery=x2−4xy = x^2 - 4x: B; y=x+3y = x + 3: D; y=x3−2y = x^3 - 2: E; y=1xy = \frac{1}{x}: C; y=5−2xy = 5 - 2x: A3 marks

Worked solution Checked against the mark scheme

y=x2−4xy = x^2 - 4x is a U-shaped curve through the origin: B

y=x+3y = x + 3 slopes up and crosses the yy-axis above O: D

y=x3−2y = x^3 - 2 is the S-shaped cubic: E

y=1xy = \frac{1}{x} has two separate branches: C

y=5−2xy = 5 - 2x slopes down: A

Watch out: Mixing up the two straight lines by ignoring the sign of the gradient.

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