Edexcel GCSE Maths · 1MA1

June 2023 Paper 1 Foundation

Non-calculator · 31 questions · 80 marks · 1 hour 30 minutes. Try each question on paper, then press "Show answer".

Question 1

Percentages1 markGrade 1No calculator
Convert a percentage into a decimal.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 1.

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Answer0.380.381 mark

Worked solution Checked against the mark scheme

Per cent means out of 100, so divide by 100.

38÷100=0.3838 \div 100 = 0.38

Watch out: Writing 3.8

Question 2

Fractions1 markGrade 1No calculator
Work out what fraction of a ten-part shape is shaded.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 2.

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Answer310\frac{3}{10}1 mark

Worked solution Checked against the mark scheme

The shape is split into 10 equal triangles and 3 of them are shaded.

So the fraction shaded is 310\frac{3}{10}.

Watch out: Writing the ratio 3 : 10 or 3 : 7 instead of a fraction.

Question 3

Pick out the smallest decimal from a short list.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 3.

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Answer0.50.51 mark

Worked solution Checked against the mark scheme

Compare the whole-number parts first: only 0.5 starts with 0.

So the smallest is 0.50.5.

Watch out: Choosing 1.3 by looking only at the digits after the point.

Question 4

Add a positive number to a negative number.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 4.

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Answer−4-41 mark

Worked solution Checked against the mark scheme

Start at −9-9 on a number line and move 5 to the right.

−9+5=−4-9 + 5 = -4

Watch out: Giving 4 or −14.

Question 5

Forming and solving linear equations1 markGrade 1No calculator
Solve a one-step linear equation.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 5.

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Answerp=5p = 51 mark

Worked solution Checked against the mark scheme

Add 2 to both sides.

p=3+2=5p = 3 + 2 = 5

Watch out: Subtracting instead of adding, giving 1.

Question 6

Circles: parts, circumference and area1 markGrade 1No calculator
Spot which label on a circle diagram is wrong and say why.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 6.

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AnswerThe line labelled diameter only goes from the centre to the edge, so it is a radius1 mark

Worked solution Checked against the mark scheme

The labelled line starts at the centre and stops at the circle.

A line like that is a radius. A diameter goes right across the circle through the centre, so the 'Diameter' label is wrong.

Watch out: Just saying 'a label is wrong' without naming which or why.

Question 7

Factors, multiples and primes2 marksGrade 1No calculator
List three different factors of a two-digit number.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 7.

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AnswerAny three of 1,2,4,5,10,201, 2, 4, 5, 10, 202 marks

Worked solution Checked against the mark scheme

Find the factor pairs of 20: 1×201 \times 20, 2×102 \times 10, 4×54 \times 5.

So the factors are 1, 2, 4, 5, 10, 20. Any three of these will do, e.g. 2, 4, 5.

Watch out: Writing multiples of 20 such as 40 or 60.

Question 8

Angle facts and parallel lines3 marksGrade 2No calculator
Find a reflex angle at a point and explain why a given angle is not obtuse.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 8.

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(a)310∘310^\circ2 marks
(b)50∘50^\circ is less than 90∘90^\circ, so it is acute, not obtuse1 mark

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(a) Angles around a point add up to 360∘360^\circ.

x=360−50=310∘x = 360 - 50 = 310^\circ

(b) An obtuse angle is between 90∘90^\circ and 180∘180^\circ. 50∘50^\circ is less than 90∘90^\circ, so it is an acute angle.

Watch out: Using 180 instead of 360 in (a), giving 130.

Question 9

Coordinates and straight-line graphs4 marksGrade 2No calculator
Read and plot coordinates, find a midpoint and draw a horizontal line on a grid.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 9.

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(a)(5,2)(5, 2)1 mark
(b)Point CC plotted at (4,−2)(4, -2)1 mark
(c)(1,3)(1, 3)1 mark
(d)Horizontal line through y=−4y = -41 mark

Worked solution Checked against the mark scheme

(a) BB is 5 across and 2 up: (5,2)(5, 2).

(b) Go 4 right and 2 down, and mark CC.

(c) A=(−3,4)A = (-3, 4). Midpoint =(−3+52,4+22)=(1,3)= \left(\frac{-3+5}{2}, \frac{4+2}{2}\right) = (1, 3)

(d) y=−4y = -4 is the horizontal line through every point with yy-coordinate −4-4.

Watch out: Drawing a vertical line x = −4 in (d).

Question 10

Decide whether £15 covers a set of plates bought using a half-price offer.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 10.

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AnswerYes: the plates cost £14.40, which is less than £154 marks

Worked solution Checked against the mark scheme

Large plates: 6×£2=£126 \times £2 = £12

Each small plate is half price: 80p÷2=40p80\text{p} \div 2 = 40\text{p}, so 6×40p=£2.406 \times 40\text{p} = £2.40

Total =£12+£2.40=£14.40= £12 + £2.40 = £14.40

£14.40<£15£14.40 < £15, so yes, he has enough (with 60p left over).

Watch out: Forgetting to halve the small plate price, getting £16.80.

Question 11

Rounding and estimation6 marksGrade 3No calculator
Subtract to find unsold tickets, estimate ticket income by rounding, and say if the estimate is too high or low.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 11.

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(a)2482482 marks
(b)£11 0003 marks
(c)Overestimate, because every value was rounded up1 mark

Worked solution Checked against the mark scheme

(a) 700−452=248700 - 452 = 248

(b) Round to 1 s.f.: 300×£10=£3000300 \times £10 = £3000 and 400×£20=£8000400 \times £20 = £8000

Estimate =£3000+£8000=£11 000= £3000 + £8000 = £11\,000

(c) Overestimate: all four numbers were rounded up, so the true total is smaller.

Watch out: In (c), saying underestimate or talking about rounding the final answer.

Question 12

Averages and spread2 marksGrade 2No calculator
Find the mean of six whole numbers.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 12.

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Answer772 marks

Worked solution Checked against the mark scheme

Add them: 13+5+4+9+3+8=4213 + 5 + 4 + 9 + 3 + 8 = 42

Divide by how many there are: 42÷6=742 \div 6 = 7

Watch out: Dividing by 5 or giving the median.

Question 13

Expanding brackets and simplifying4 marksGrade 3No calculator
Simplify a simple algebraic fraction, collect like terms, and factorise a linear expression.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 13.

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(a)5a5a1 mark
(b)19−2b+5c19 - 2b + 5c2 marks
(c)2(4d−3)2(4d - 3)1 mark

Worked solution Checked against the mark scheme

(a) 15a3=5a\frac{15a}{3} = 5a

(b) bb terms: 5b−7b=−2b5b - 7b = -2b. cc terms: 4c+c=5c4c + c = 5c.

So 19−2b+5c19 - 2b + 5c

(c) The highest common factor of 8 and 6 is 2: 8d−6=2(4d−3)8d - 6 = 2(4d - 3)

Watch out: In (b), writing +2b instead of −2b, or treating c as 0c.

Question 14

Ratio5 marksGrade 3No calculator
Find a percentage complement, turn a ratio into a fraction, and compare numbers of children on two days.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 14.

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(a)27%27\%1 mark
(b)27\frac{2}{7}1 mark
(c)No: 350 children on Friday, 450 on Saturday3 marks

Worked solution Checked against the mark scheme

(a) 100−73=27%100 - 73 = 27\%

(b) Total parts =2+5=7= 2 + 5 = 7, so adults are 27\frac{2}{7}.

(c) Friday: 0.7×500=3500.7 \times 500 = 350 children

Saturday: 720÷8×5=450720 \div 8 \times 5 = 450 children

450>350450 > 350, so no, Kasim is wrong.

Watch out: In (b), writing 2/5 instead of 2/7.

Question 15

Fractions2 marksGrade 3No calculator
Multiply two proper fractions and simplify.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 15.

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Answer514\frac{5}{14}2 marks

Worked solution Checked against the mark scheme

Multiply tops and bottoms: 6×57×12=3084\frac{6 \times 5}{7 \times 12} = \frac{30}{84}

Divide top and bottom by 6: 514\frac{5}{14}

Watch out: Stopping at 30/84 without simplifying.

Question 16

Direct and inverse proportion2 marksGrade 2No calculator
Scale a recipe up to find how much of one ingredient is needed.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 16.

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Answer750750 g2 marks

Worked solution Checked against the mark scheme

60 biscuits is 60÷20=360 \div 20 = 3 times as many.

Flour: 250×3=750250 \times 3 = 750 g

Watch out: Using the butter amount instead of the flour, getting 450.

Question 17

Percentages4 marksGrade 3No calculator
Find what percentage of a bag of counters are one colour when two colours share the remainder equally.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 17.

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Answer27.5%27.5\%4 marks

Worked solution Checked against the mark scheme

Yellow and green together: 200−38−52=110200 - 38 - 52 = 110

Yellow: 110÷2=55110 \div 2 = 55

Percentage: 55200×100=27.5%\frac{55}{200} \times 100 = 27.5\%

Watch out: Giving 55% by forgetting to halve.

Question 18

Write a formula for the total number of apples from bags and crates.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 18.

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AnswerT=5b+28cT = 5b + 28c3 marks

Worked solution Checked against the mark scheme

Each bag has 5 apples, so bb bags hold 5b5b.

Each crate has 28 apples, so cc crates hold 28c28c.

T=5b+28cT = 5b + 28c

Watch out: Leaving out 'T =' or writing b + c = T.

Question 19

Sequences and the nth term2 marksGrade 4No calculator
Find the nth term of an arithmetic sequence with a negative first term.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 19.

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Answer8n−138n - 132 marks

Worked solution Checked against the mark scheme

The terms go up by 8, so start with 8n8n: 8, 16, 24, ...

Each term of the sequence is 13 less: 8−13=−58 - 13 = -5.

nth term =8n−13= 8n - 13

Watch out: Writing 8n − 5 by using the first term as the constant.

Question 20

Calculating with integers, decimals and negatives3 marksGrade 4No calculatorOn both tiers
Divide one decimal by another without a calculator.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 20.

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Answer56.456.43 marks

Worked solution Checked against the mark scheme

Multiply both numbers by 100: 8.46÷0.15=846÷158.46 \div 0.15 = 846 \div 15

15×56=84015 \times 56 = 840, remainder 6, and 6÷15=0.46 \div 15 = 0.4

So the answer is 56.456.4

Watch out: Misplacing the decimal point, giving 5.64 or 564.

Question 21

Fractions3 marksGrade 4No calculator
Subtract one mixed number from another and give a mixed number.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 21.

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Answer4784\frac{7}{8}3 marks

Worked solution Checked against the mark scheme

Make improper fractions: 738=5987\frac{3}{8} = \frac{59}{8}, 212=2082\frac{1}{2} = \frac{20}{8}

598−208=398=478\frac{59}{8} - \frac{20}{8} = \frac{39}{8} = 4\frac{7}{8}

Watch out: Doing 38−12\frac{3}{8} - \frac{1}{2} the wrong way round, giving 5185\frac{1}{8}.

Question 22

Volume and surface area4 marksGrade 4No calculatorOn both tiers
Use a cube's surface area to find its volume.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 22.

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Answer1251254 marks

Worked solution Checked against the mark scheme

A cube has 6 equal faces: 150÷6=25150 \div 6 = 25 cm²

Edge length: 25=5\sqrt{25} = 5 cm

Volume: 5×5×5=1255 \times 5 \times 5 = 125 cm³

Watch out: Dividing by 4 or cube-rooting 150.

Question 23

Charts, graphs and time series2 marksGrade 4No calculatorOn both tiers
Draw a frequency polygon from a grouped frequency table.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 23.

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AnswerPoints at (2.5,8),(7.5,24),(12.5,13),(17.5,11),(22.5,4)(2.5, 8), (7.5, 24), (12.5, 13), (17.5, 11), (22.5, 4) joined with straight lines2 marks

Worked solution Checked against the mark scheme

Plot each frequency above the middle of its class: 2.5, 7.5, 12.5, 17.5, 22.5.

Points: (2.5,8),(7.5,24),(12.5,13),(17.5,11),(22.5,4)(2.5, 8), (7.5, 24), (12.5, 13), (17.5, 11), (22.5, 4)

Join them in order with a ruler. Do not join the last point back to the first.

Watch out: Plotting at the class boundaries (0, 5, 10, …) instead of the midpoints.

Question 24

Venn diagrams and sets5 marksGrade 4No calculatorOn both tiers
Fill in a Venn diagram for odd and square numbers up to 10, then find the probability of not being square.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 24.

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(a)AA only: 3, 5, 7; both: 1, 9; BB only: 4; outside: 2, 6, 8, 103 marks
(b)710\frac{7}{10}2 marks

Worked solution Checked against the mark scheme

(a) Odd: 1, 3, 5, 7, 9. Square: 1, 4, 9.

In both: 1, 9. Odd only: 3, 5, 7. Square only: 4. Neither: 2, 6, 8, 10.

(b) B′B' means not square: 10−3=710 - 3 = 7 numbers, so P=710P = \frac{7}{10}

Watch out: Forgetting that 1 is a square number.

Question 25

Scatter graphs and correlation3 marksGrade 4No calculatorOn both tiers
Describe the correlation on a scatter graph and use it to estimate a value.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 25.

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(a)Positive correlation: older babies tend to weigh more1 mark
(b)About 3.5 months (accept 2.5 to 4.5)2 marks

Worked solution Checked against the mark scheme

(a) As age increases, weight increases: positive correlation.

(b) Draw a line of best fit. Go across from 5.8 kg to the line, then down to the age axis.

This gives about 3.5 months.

Watch out: In (a), writing just 'positive' without saying correlation or describing the trend.

Question 26

Percentage change and reverse percentages2 marksGrade 4No calculatorOn both tiers
Work backwards from the amount a percentage increase adds to find the original price.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 26.

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Answer£12002 marks

Worked solution Checked against the mark scheme

20% of the price is £240.

10% is £120, so 100% is 120×10=£1200120 \times 10 = £1200

Watch out: Adding 20% to 240 or finding 20% of 240.

Question 27

Speed, density and pressure3 marksGrade 5No calculatorOn both tiers
Find the pressure a cylinder exerts using its volume, height and force.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 27.

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Answer333 marks

Worked solution Checked against the mark scheme

Volume = base area × height, so base area =1200÷40=30= 1200 \div 40 = 30 cm²

Pressure =9030=3= \frac{90}{30} = 3 newtons/cm²

Watch out: Dividing 90 by 1200 without finding the base area.

Question 28

Simultaneous equations1 markGrade 5No calculatorOn both tiers
Read the solution of a pair of simultaneous equations from where their graphs cross.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 28.

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Answerx=6, y=−2x = 6,\ y = -21 mark

Worked solution Checked against the mark scheme

The solution is where the two lines meet, at (6,−2)(6, -2).

Check: 2−2(−2)=62 - 2(-2) = 6 ✓ and 2(−2)=−4=3(6)−222(-2) = -4 = 3(6) - 22 ✓

So x=6x = 6, y=−2y = -2.

Watch out: Swapping x and y.

Question 29

Powers, roots and indices2 marksGrade 5No calculator
Use index laws to evaluate a product and quotient of powers of 4.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 29.

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Answer16162 marks

Worked solution Checked against the mark scheme

Multiplying: add the powers, −6+9=3-6 + 9 = 3, so the top is 434^3.

Dividing by 414^1: subtract the powers, 43−1=42=164^{3-1} = 4^2 = 16

Watch out: Stopping at 424^2 or writing 8.

Question 30

Pythagoras and trigonometry1 markGrade 5No calculator
State the exact value of cos 60°.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 30.

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Answer12\frac{1}{2}1 mark

Worked solution Checked against the mark scheme

This is one of the exact trig values to learn.

cos⁡60∘=12\cos 60^\circ = \frac{1}{2}

Watch out: Confusing with sin 60°, giving √3/2.

Question 31

Tree diagrams and combined events2 marksGrade 5No calculator
Use a tree diagram to find the probability of two particular outcomes happening together.

© Pearson Education Ltd. June 2023 Paper 1 (Foundation, non-calculator), question 31.

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Answer0.060.062 marks

Worked solution Checked against the mark scheme

Follow the branches: home on Monday (0.2), then office on Friday (0.3).

Multiply along the branches: 0.2×0.3=0.060.2 \times 0.3 = 0.06

Watch out: Adding the probabilities to get 0.5.

Finished the paper?

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