Edexcel GCSE Maths · 1MA1

November 2018 Paper 3 Foundation

Calculator · 26 questions · 80 marks · 1 hour 30 minutes. Try each question on paper, then press "Show answer".

Question 1

Find the missing number that makes a decimal sum reach 100, then the missing fraction that makes a sum reach 1.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 1.

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(i)43.743.71 mark
(ii)57\frac{5}{7}1 mark

Worked solution Checked against the mark scheme

(i) 100−56.3=43.7100 - 56.3 = 43.7

(ii) One whole is 77\frac{7}{7}, so 77−27=57\frac{7}{7} - \frac{2}{7} = \frac{5}{7}

Watch out: In (i), getting 44.7 or 43.3 by mis-handling the decimal when subtracting from 100.

Question 2

Convert a percentage into a fraction.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 2.

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Answer3100\frac{3}{100}1 mark

Worked solution Checked against the mark scheme

Per cent means out of 100, so 3%=31003\% = \frac{3}{100}

Watch out: Writing 310\frac{3}{10}.

Question 3

Powers, roots and indices1 markGrade 2Calculator
Find the square root of a decimal.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 3.

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Answer1.21.21 mark

Worked solution Checked against the mark scheme

1.2×1.2=1.441.2 \times 1.2 = 1.44, so 1.44=1.2\sqrt{1.44} = 1.2

Watch out: Halving the number instead of square rooting it (0.72).

Question 4

Fractions1 markGrade 1Calculator
Find a unit fraction of a whole number.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 4.

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Answer90901 mark

Worked solution Checked against the mark scheme

18\frac{1}{8} of 720 means 720÷8=90720 \div 8 = 90

Watch out: Multiplying by 8 instead of dividing.

Question 5

3D shapes, plans and elevations2 marksGrade 1Calculator
Name a pictured 3-D solid and count its edges.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 5.

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(a)Cuboid1 mark
(b)12121 mark

Worked solution Checked against the mark scheme

(a) Six rectangular faces, so it is a cuboid.

(b) 4 edges on the top, 4 on the bottom and 4 upright edges: 4+4+4=124 + 4 + 4 = 12

Watch out: Counting only the edges that can be seen, or confusing edges with vertices (8).

Question 6

Mark the chance of an odd score on a fair dice on a probability scale, then give the probability of rolling above 4.

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(a)Cross at 12\frac{1}{2}1 mark
(b)26\frac{2}{6}1 mark

Worked solution Checked against the mark scheme

(a) Odd numbers are 1, 3, 5: that is 3 out of 6, so 36=12\frac{3}{6} = \frac{1}{2}. Put the cross in the middle.

(b) Numbers greater than 4 are 5 and 6, so the probability is 26=13\frac{2}{6} = \frac{1}{3}

Watch out: In (b), including 4 and giving 36\frac{3}{6}.

Question 7

Units and converting units2 marksGrade 1Calculator
Add a height in centimetres to a height in metres.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 7.

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Answer1.941.94 m (or 194194 cm)2 marks

Worked solution Checked against the mark scheme

Change 6 cm to metres: 6÷100=0.066 \div 100 = 0.06 m.

1.88+0.06=1.941.88 + 0.06 = 1.94 m (or 188+6=194188 + 6 = 194 cm).

Watch out: Adding 6 straight on to 1.88 to get 7.88.

Question 8

Direct and inverse proportion4 marksGrade 2Calculator
Decide whether £50 covers 20 pens and 20 folders, given prices for smaller packs.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 8.

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AnswerYes: the total is £46.20 (£3.80 left)4 marks

Worked solution Checked against the mark scheme

One pen: 2.38÷2=£1.192.38 \div 2 = £1.19, so 20 pens: 20×1.19=£23.8020 \times 1.19 = £23.80

One folder: 5.60÷5=£1.125.60 \div 5 = £1.12, so 20 folders: 20×1.12=£22.4020 \times 1.12 = £22.40

Total: 23.80+22.40=£46.2023.80 + 22.40 = £46.20

£46.20<£50£46.20 < £50, so yes, Ben has enough (with £3.80 left).

Watch out: Multiplying £2.38 by 20 instead of by 10.

Question 9

Name one shape on a grid and pick out the two congruent shapes.

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(a)Trapezium1 mark
(b)C and D1 mark

Worked solution Checked against the mark scheme

(a) Shape E has exactly one pair of parallel sides, so it is a trapezium.

(b) Congruent shapes are exactly the same shape and size (they may be turned). C and D match.

Watch out: Choosing two shapes that are similar (same shape, different size) rather than congruent.

Question 10

Transformations1 markGrade 1Calculator
Reflect a shaded shape in a given mirror line on a grid.

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AnswerCorrect reflection drawn1 mark

Worked solution Checked against the mark scheme

Take each corner of the shape in turn and count its distance to the mirror line.

Plot the image corner the same distance on the other side, then join the corners up.

Watch out: Translating the shape across the line instead of flipping it.

Question 11

Percentages3 marksGrade 3Calculator
Given the number of women and the percentage who are men, find the total at a meeting.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 11.

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Answer40403 marks

Worked solution Checked against the mark scheme

Men are 30%, so women are 100−30=70%100 - 30 = 70\%

70%70\% is 28, so 10%10\% is 28÷7=428 \div 7 = 4

100%100\% is 4×10=404 \times 10 = 40 people.

Watch out: Working out 30% of 28 and adding it on, giving 36.4.

Question 12

Charts, graphs and time series3 marksGrade 3Calculator
Draw an accurate pie chart from a frequency table of favourite vegetables.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 12.

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AnswerPie chart with Peas 144°144°, Carrots 96°96°, Mushrooms 120°120°, labelled3 marks

Worked solution Checked against the mark scheme

Each person is worth 360÷60=6°360 \div 60 = 6°

Peas: 24×6=144°24 \times 6 = 144°; Carrots: 16×6=96°16 \times 6 = 96°; Mushrooms: 20×6=120°20 \times 6 = 120°

Check: 144+96+120=360°144 + 96 + 120 = 360°. Draw the sectors with a protractor and label each one.

Watch out: Using the frequencies as the angles directly.

Question 13

Find how many calendars were sold from the total takings and the other items sold.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 13.

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Answer50504 marks

Worked solution Checked against the mark scheme

Books: 45×1.20=£5445 \times 1.20 = £54

Candles: 34×1.50=£5134 \times 1.50 = £51

Left for calendars: 150−54−51=£45150 - 54 - 51 = £45

90p is £0.90, so 45÷0.90=5045 \div 0.90 = 50 calendars.

Watch out: Dividing £45 by 90 without changing pence to pounds.

Question 14

Complete a probability table for a spinner, find the least likely outcome and estimate a frequency from 60 spins.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 14.

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(a)0.30.31 mark
(b)441 mark
(c)12122 marks

Worked solution Checked against the mark scheme

(a) Probabilities add to 1: 1−(0.2+0.4+0.1)=0.31 - (0.2 + 0.4 + 0.1) = 0.3

(b) The smallest probability is 0.1, which is for 4.

(c) Expected number of 1s: 0.2×60=120.2 \times 60 = 12

Watch out: In (b), writing the probability 0.1 instead of the number 4.

Question 15

Factors, multiples and primes3 marksGrade 3Calculator
Count how many whole numbers from 1 to 100 are multiples of both 3 and 5.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 15.

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Answer663 marks

Worked solution Checked against the mark scheme

A card with both marks is a multiple of 3 and of 5, so a multiple of 15.

Multiples of 15 up to 100: 15, 30, 45, 60, 75, 90.

That is 6 cards.

Watch out: Rounding 100÷15=6.67100 \div 15 = 6.67 up to 7.

Question 16

Ratio2 marksGrade 3Calculator
Write a ratio of two masses in its simplest form.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 16.

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Answer30:130:12 marks

Worked solution Checked against the mark scheme

450:15450 : 15

Divide both sides by 15: 30:130 : 1

Watch out: Writing the ratio the wrong way round as 1 : 30.

Question 17

Forming and solving linear equations5 marksGrade 4Calculator
Form an equation for the perimeter of a symmetrical pentagon with algebraic sides, then solve it.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 17.

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(a)4x+2(2x+1)+2(x+2)=10x+6=184x + 2(2x+1) + 2(x+2) = 10x + 6 = 183 marks
(b)x=1.2x = 1.22 marks

Worked solution Checked against the mark scheme

(a) By symmetry DE=AB=2x+1DE = AB = 2x + 1 and CD=BC=x+2CD = BC = x + 2

Perimeter =4x+2(2x+1)+2(x+2)=4x+4x+2+2x+4=10x+6= 4x + 2(2x + 1) + 2(x + 2) = 4x + 4x + 2 + 2x + 4 = 10x + 6

The perimeter is 18, so 10x+6=1810x + 6 = 18

(b) 10x=1210x = 12, so x=1.2x = 1.2

Watch out: In (a), adding only the three given sides and forgetting the two matching sides.

Question 18

Percentages4 marksGrade 3Calculator
Add VAT to a price, take off a deposit and split the rest into equal payments.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 18.

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Answer£1204£12044 marks

Worked solution Checked against the mark scheme

VAT: 20%20\% of 14 200=284014\,200 = 2840

Total cost: 14 200+2840=£17 04014\,200 + 2840 = £17\,040

After deposit: 17 040−5000=£12 04017\,040 - 5000 = £12\,040

Each payment: 12 040÷10=£120412\,040 \div 10 = £1204

Watch out: Forgetting the VAT and getting £920.

Question 19

Inequalities7 marksGrade 4Calculator
Show a strict inequality on a number line, list integers satisfying a double inequality, and solve a linear inequality.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 19.

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(a)Open circle at 4 with an arrow to the left2 marks
(b)4,5,6,74, 5, 6, 72 marks
(c)x⩾6x \geqslant 63 marks

Worked solution Checked against the mark scheme

(a) x<4x < 4 does not include 4, so draw an open circle at 4 and an arrow pointing left.

(b) yy is more than 3 and at most 7: 4,5,6,74, 5, 6, 7

(c) 3x+5⩾x+173x + 5 \geqslant x + 17

2x+5⩾172x + 5 \geqslant 17

2x⩾122x \geqslant 12, so x⩾6x \geqslant 6

Watch out: In (b), including 3 or leaving out 7.

Question 20

Rounding and estimation3 marksGrade 3CalculatorOn both tiers
Round a number to 3 significant figures and evaluate a calculation with a square root and powers on a calculator.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 20.

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(a)736073601 mark
(b)0.10779813560.10779813562 marks

Worked solution Checked against the mark scheme

(a) The 4th figure is 7, so round up: 7357→73607357 \to 7360

(b) Top: 17+16=33=5.7445…\sqrt{17 + 16} = \sqrt{33} = 5.7445\ldots

Bottom: 7.32=53.297.3^2 = 53.29

5.7445…÷53.29=0.10779813565.7445\ldots \div 53.29 = 0.1077981356

Watch out: In (a), writing 736 and losing the place value.

Question 21

Percentage change and reverse percentages3 marksGrade 4CalculatorOn both tiers
Work out a percentage increase between two yearly costs.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 21.

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Answer260.4%260.4\%3 marks

Worked solution Checked against the mark scheme

Increase: 883−245=638883 - 245 = 638

Percentage increase: 638245×100=260.4%\frac{638}{245} \times 100 = 260.4\%

Watch out: Dividing by the new price (883) instead of the original.

Question 22

Quadratic graphs5 marksGrade 4CalculatorOn both tiers
Complete a table of values for a quadratic, draw its graph and use it to estimate a root.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 22.

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(a)2,−4,2,82, -4, 2, 8 (for x=−3,−1,2,3x = -3, -1, 2, 3)2 marks
(b)Smooth U-shaped curve through the points2 marks
(c)x≈1.6x \approx 1.6 or x≈−2.6x \approx -2.61 mark

Worked solution Checked against the mark scheme

(a) x=−3x = -3: 9−3−4=29 - 3 - 4 = 2; x=−1x = -1: 1−1−4=−41 - 1 - 4 = -4; x=2x = 2: 4+2−4=24 + 2 - 4 = 2; x=3x = 3: 9+3−4=89 + 3 - 4 = 8

(b) Plot all seven points and join with a smooth curve, dipping just below −4-4 between x=−1x = -1 and x=0x = 0.

(c) The roots are where the curve crosses the xx-axis: about 1.61.6 or −2.6-2.6

Watch out: In (a), working out −32-3^2 as −9-9.

Question 23

Averages and spread6 marksGrade 4CalculatorOn both tiers
Read a grouped bar chart to find a percentage, then show an estimate of the mean from grouped data.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 23.

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(a)5%5\%2 marks
(b)380÷40=9.5380 \div 40 = 9.54 marks

Worked solution Checked against the mark scheme

(a) 2 students bought 20 to 24 books: 240×100=5%\frac{2}{40} \times 100 = 5\%

(b) Frequencies 11, 8, 13, 6, 2 and midpoints 2, 7, 12, 17, 22

11×2+8×7+13×12+6×17+2×22=22+56+156+102+44=38011 \times 2 + 8 \times 7 + 13 \times 12 + 6 \times 17 + 2 \times 22 = 22 + 56 + 156 + 102 + 44 = 380

Mean ≈380÷40=9.5\approx 380 \div 40 = 9.5

Watch out: Dividing the total by 5 (the number of groups) instead of 40.

Question 24

Speed, density and pressure4 marksGrade 4CalculatorOn both tiers
Scale a race time up to a longer distance at the same speed, then say how rising speed affects that answer.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 24.

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(a)2 minutes 48 seconds3 marks
(b)It would take less time than the answer to (a)1 mark

Worked solution Checked against the mark scheme

(a) 1 min 54 s =114= 114 s

Time =700475×114=168= \frac{700}{475} \times 114 = 168 s

168168 s =2= 2 minutes 4848 seconds

(b) If she speeds up over a longer race, she will finish more quickly, so the real time is less than 2 min 48 s.

Watch out: Treating 1 minute 54 seconds as 1.54 minutes.

Question 25

Pythagoras and trigonometry4 marksGrade 5CalculatorOn both tiers
Use an angle ratio in a right-angled triangle to find the angles, then use trigonometry to find the hypotenuse.

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Answer17.317.3 cm4 marks

Worked solution Checked against the mark scheme

Angles A and B share 180−90=90°180 - 90 = 90° in the ratio 3:23 : 2 (B : A)

One part =90÷5=18°= 90 \div 5 = 18°, so A=36°A = 36° and B=54°B = 54°

AC is next to angle A and AB is the hypotenuse: cos⁡36°=14AB\cos 36° = \frac{14}{AB}

AB=14cos⁡36°=17.3AB = \frac{14}{\cos 36°} = 17.3 cm

Watch out: Giving A the larger angle, 54°, and getting 24.1 cm.

Question 26

Sequences and the nth term2 marksGrade 4Calculator
Find the nth term of an arithmetic sequence.

© Pearson Education Ltd. November 2018 Paper 3 (Foundation, calculator), question 26.

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Answer6n−16n - 12 marks

Worked solution Checked against the mark scheme

The terms go up by 6, so start with 6n6n.

6n6n gives 6, 12, 18, 24. Each term is 1 less, so the nth term is 6n−16n - 1.

Watch out: Writing n + 6.

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