Edexcel GCSE Maths · 1MA1

November 2023 Paper 2 Foundation

Calculator · 30 questions · 80 marks · 1 hour 30 minutes. Try each question on paper, then press "Show answer".

Question 1

Factors, multiples and primes1 markGrade 1Calculator
Give any two numbers that divide exactly into 18.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 1.

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AnswerAny two of 1, 2, 3, 6, 9, 181 mark

Worked solution Checked against the mark scheme

Factor pairs of 18: 1×181 \times 18, 2×92 \times 9, 3×63 \times 6.

So the factors are 1, 2, 3, 6, 9 and 18. Any two of these, e.g. 2 and 9.

Watch out: Giving multiples of 18 such as 36 instead of factors.

Question 2

Convert a one-decimal-place number into a fraction.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 2.

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Answer910\frac{9}{10}1 mark

Worked solution Checked against the mark scheme

The 9 is in the tenths column, so 0.9=9100.9 = \frac{9}{10}.

Watch out: Writing 9100\frac{9}{100} or 19\frac{1}{9}.

Question 3

Units and converting units1 markGrade 1Calculator
Convert a length in metres into centimetres.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 3.

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Answer700 cm1 mark

Worked solution Checked against the mark scheme

There are 100 cm in 1 m.

7×100=7007 \times 100 = 700 cm

Watch out: Multiplying by 10 or 1000 instead of 100.

Question 4

Powers, roots and indices1 markGrade 1Calculator
Give a square number lying between 10 and 50.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 4.

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AnswerAny one of 16, 25, 36, 491 mark

Worked solution Checked against the mark scheme

Square the whole numbers: 42=164^2 = 16, 52=255^2 = 25, 62=366^2 = 36, 72=497^2 = 49.

Any of these works, e.g. 25.

Watch out: Giving 4 or 5, the square roots, rather than the squares.

Question 5

Percentages1 markGrade 1Calculator
Find half of an amount.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 5.

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Answer1201 mark

Worked solution Checked against the mark scheme

50% means half.

240÷2=120240 \div 2 = 120

Watch out: Dividing by 50 instead of halving.

Question 6

Work out an hourly rate of pay from a total wage and number of hours.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 6.

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Answer£12.502 marks

Worked solution Checked against the mark scheme

Pay per hour == total pay ÷\div hours

50÷4=12.550 \div 4 = 12.5, so £12.50 per hour.

Watch out: Writing £12.5 is fine, but multiplying 50 by 4 to get 200 is not.

Question 7

3D shapes, plans and elevations2 marksGrade 1Calculator
Name a pictured solid and sketch a triangular prism.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 7.

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(a)Cone1 mark
(b)A sketch of a prism with two triangular ends joined by three rectangular faces1 mark

Worked solution Checked against the mark scheme

(a) The solid has a circular base and comes to a point at the top, so it is a cone.

(b) Draw a triangle, draw an identical triangle slightly across and up from it, then join matching corners with three parallel lines.

Watch out: In (b), drawing a square-based pyramid or a flat triangle.

Question 8

Add up the cost of several sports items bought at given prices and show the total is within a budget.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 8.

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AnswerTotal cost £188.50, which is less than £200 (or £11.50 left)4 marks

Worked solution Checked against the mark scheme

Footballs: 5×9.50=47.505 \times 9.50 = 47.50

Hockey sticks: 6 sticks is 3 lots of 2, so 3×30=903 \times 30 = 90

Cricket bats: 2×23=462 \times 23 = 46

Tennis balls: 4 balls cost 55

Total =47.50+90+46+5=£188.50= 47.50 + 90 + 46 + 5 = £188.50, which is less than £200, so he can buy everything.

Watch out: Paying £30 for each hockey stick instead of £30 for every two.

Question 9

List every shirt-and-tie combination from three shirt colours and three tie styles.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 9.

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AnswerWP, WS, WC, BP, BS, BC, GP, GS, GC2 marks

Worked solution Checked against the mark scheme

Work systematically: fix the shirt, then go through the ties.

White: WP, WS, WC

Blue: BP, BS, BC

Grey: GP, GS, GC

That is 3×3=93 \times 3 = 9 combinations.

Watch out: Missing combinations by not listing in order.

Question 10

Ratio2 marksGrade 2Calculator
Write the ratio of two counter colours in its simplest form.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 10.

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Answer3:53 : 52 marks

Worked solution Checked against the mark scheme

Red : blue =24:40= 24 : 40

The highest common factor of 24 and 40 is 8.

24÷8=324 \div 8 = 3 and 40÷8=540 \div 8 = 5, so the ratio is 3:53 : 5.

Watch out: Writing the ratio the wrong way round as 5 : 3.

Question 11

Choose probability words for rolling a 3 and for rolling an odd number on a fair dice.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 11.

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(a)Unlikely1 mark
(b)Evens1 mark

Worked solution Checked against the mark scheme

(a) Only 1 of the 6 faces is a 3, so the probability is 16\frac{1}{6}: unlikely.

(b) The odd numbers are 1, 3 and 5, so 3 out of 6, which is 12\frac{1}{2}: evens.

Watch out: Calling a 1 in 6 chance impossible.

Question 12

Speed, density and pressure2 marksGrade 2Calculator
Find the distance covered from an average speed and a time.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 12.

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Answer111 miles2 marks

Worked solution Checked against the mark scheme

Distance == speed ×\times time

37×3=11137 \times 3 = 111 miles

Watch out: Dividing 37 by 3 instead of multiplying.

Question 13

Area and perimeter2 marksGrade 2Calculator
Explain the error in a rectangle area calculation and why an area given in cm is wrong.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 13.

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(a)He should only multiply length by width once: 5×4=20 cm25 \times 4 = 20\text{ cm}^21 mark
(b)Area must be in square units, e.g. cm², not cm1 mark

Worked solution Checked against the mark scheme

(a) Area of a rectangle == length ×\times width =5×4=20 cm2= 5 \times 4 = 20\text{ cm}^2. Milo multiplied all four side lengths together, which uses each measurement twice.

(b) Area is measured in square units. An answer in cm is a length, so it should be in cm2\text{cm}^2.

Watch out: In (a), saying he should have added the sides, which gives the perimeter, not the area.

Question 14

Use the price of flour to find the price of sugar, then cost a different combination of the two.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 14.

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Answer£6.954 marks

Worked solution Checked against the mark scheme

1 kg flour: 4.05÷3=1.354.05 \div 3 = 1.35

5 kg flour: 5×1.35=6.755 \times 1.35 = 6.75, so 6 kg sugar costs 11.85−6.75=5.1011.85 - 6.75 = 5.10

1 kg sugar: 5.10÷6=0.855.10 \div 6 = 0.85

2 kg flour + 5 kg sugar =2×1.35+5×0.85=2.70+4.25=£6.95= 2 \times 1.35 + 5 \times 0.85 = 2.70 + 4.25 = £6.95

Watch out: Dividing £11.85 by 11 as if flour and sugar cost the same per kilogram.

Question 15

Percentages3 marksGrade 4Calculator
Find a percentage share of a sum, then how much remains after a percentage of that share is spent.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 15.

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Answer£60.483 marks

Worked solution Checked against the mark scheme

Martha's share: 0.72×120=86.400.72 \times 120 = 86.40

She keeps 100%−30%=70%100\% - 30\% = 70\% of it.

0.7×86.40=£60.480.7 \times 86.40 = £60.48

Watch out: Giving £25.92, the amount she spends, rather than what is left.

Question 16

Charts, graphs and time series4 marksGrade 4Calculator
Use facts about children and adults choosing book types to work out how many chose horror.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 16.

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Answer244 marks

Worked solution Checked against the mark scheme

Adults: 160−85=75160 - 85 = 75. Adult romance: 33−19=1433 - 19 = 14. Child adventure: 76−34=4276 - 34 = 42.

Adult horror: 75−14−34−7=2075 - 14 - 34 - 7 = 20, so 20 children chose thriller.

Child horror: 85−19−42−20=485 - 19 - 42 - 20 = 4

Total horror: 20+4=2420 + 4 = 24

Watch out: Forgetting that the number of children choosing thriller equals the adult horror number.

Question 17

Charts, graphs and time series3 marksGrade 3Calculator
Draw an ordered stem and leaf diagram with a key for sixteen heights.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 17.

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Answer16 | 0 2 8; 17 | 2 2 3 7 8; 18 | 0 0 3 4 6 8; 19 | 1 7; Key: 16 | 0 means 160 cm3 marks

Worked solution Checked against the mark scheme

Use the tens-and-hundreds digits as the stem (16, 17, 18, 19) and the units as leaves.

16 | 0 2 8

17 | 2 2 3 7 8

18 | 0 0 3 4 6 8

19 | 1 7

Key: 16 | 0 means 160 cm. Check there are 16 leaves in total.

Watch out: Leaving the leaves out of order or forgetting the key.

Question 18

Use a calculator to evaluate a fraction with sums and products, then round the result to 2 decimal places.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 18.

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(a)1.882086168…1.882086168\ldots2 marks
(b)1.881 mark

Worked solution Checked against the mark scheme

(a) Top: 9.8+6.8=16.69.8 + 6.8 = 16.6. Bottom: 4.2×2.1=8.824.2 \times 2.1 = 8.82

16.6÷8.82=1.882086168…16.6 \div 8.82 = 1.882086168\ldots

(b) The third decimal place is 2, so round down: 1.881.88

Watch out: Typing it in without brackets, so only 6.8 is divided by 4.2 × 2.1.

Question 19

Angle facts and parallel lines4 marksGrade 5Calculator
Find a missing angle in a quadrilateral joined to an equilateral triangle, using parallel lines, giving reasons.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 19.

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Answerx=78°x = 78°4 marks

Worked solution Checked against the mark scheme

Triangle BCD is equilateral, so angle DBC=60°DBC = 60° (angles in an equilateral triangle are equal).

Angle BDE=60°BDE = 60° (alternate angles are equal, since CB is parallel to DE).

Angle ABD=90°ABD = 90° (marked right angle).

Angles in a quadrilateral add up to 360°360°: x=360−90−60−132=78°x = 360 - 90 - 60 - 132 = 78°

Watch out: Giving reasons like 'Z angles' instead of 'alternate angles are equal'.

Question 20

Quadratic graphs4 marksGrade 4Calculator
Complete a table of values for a quadratic and draw its graph.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 20.

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(a)0,−2,0,40, -2, 0, 4 (for x=−1,0,2,3x = -1, 0, 2, 3)2 marks
(b)A smooth U-shaped curve through (−2,4),(−1,0),(0,−2),(1,−2),(2,0),(3,4)(-2,4), (-1,0), (0,-2), (1,-2), (2,0), (3,4)2 marks

Worked solution Checked against the mark scheme

(a) Substitute each xx into x2−x−2x^2 - x - 2:

x=−1x = -1: 1+1−2=01 + 1 - 2 = 0; x=0x = 0: −2-2; x=2x = 2: 4−2−2=04 - 2 - 2 = 0; x=3x = 3: 9−3−2=49 - 3 - 2 = 4

(b) Plot the six points and join them with a smooth curve. The lowest point is between x=0x = 0 and x=1x = 1, just below −2-2.

Watch out: Working out (−1)2(-1)^2 as −1-1, giving the wrong value at x=−1x = -1.

Question 21

Transformations2 marksGrade 5Calculator
Describe the single transformation taking one triangle to another on a coordinate grid.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 21.

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AnswerReflection in the line y=−xy = -x2 marks

Worked solution Checked against the mark scheme

Corners of A: (1,5),(3,5),(1,2)(1,5), (3,5), (1,2). Corners of B: (−5,−1),(−5,−3),(−2,−1)(-5,-1), (-5,-3), (-2,-1).

Each point (a,b)(a, b) goes to (−b,−a)(-b, -a), which is a reflection.

The mirror line is y=−xy = -x, so the answer is **reflection in the line y=−xy = -x**.

Watch out: Calling it a rotation of 180° or using the line y = x.

Question 22

Expanding brackets and simplifying6 marksGrade 4Calculator
Expand and simplify two brackets, factorise a quadratic expression fully and rearrange a linear formula.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 22.

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(a)13y−113y - 12 marks
(b)3x(2x+5)3x(2x + 5)2 marks
(c)g=f−113g = \frac{f - 11}{3}2 marks

Worked solution Checked against the mark scheme

(a) 6y−15+7y+14=13y−16y - 15 + 7y + 14 = 13y - 1

(b) The HCF of 6x26x^2 and 15x15x is 3x3x: 6x2+15x=3x(2x+5)6x^2 + 15x = 3x(2x + 5)

(c) f−11=3gf - 11 = 3g, so g=f−113g = \frac{f - 11}{3}

Watch out: In (b), taking out only 3 or only x, so the answer is not fully factorised.

Question 23

Percentage change and reverse percentages4 marksGrade 5CalculatorOn both tiers
Work out the percentage profit from ticket sales after event costs.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 23.

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Answer35%4 marks

Worked solution Checked against the mark scheme

Income: 54×7.50=£40554 \times 7.50 = £405

Costs: 100+120+80=£300100 + 120 + 80 = £300

Profit: 405−300=£105405 - 300 = £105

Percentage profit =105300×100=35%= \frac{105}{300} \times 100 = 35\%

Watch out: Dividing the profit by the income (405) instead of the costs.

Question 24

Compound interest, growth and decay2 marksGrade 5CalculatorOn both tiers
Find the value of an investment after two years of compound interest.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 24.

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Answer£4811.202 marks

Worked solution Checked against the mark scheme

Multiplier for 3.4% interest: 1.0341.034

4500×1.0342=4811.2024500 \times 1.034^2 = 4811.202, so £4811.20

Watch out: Using simple interest to get £4806.

Question 25

Forming and solving linear equations3 marksGrade 4CalculatorOn both tiers
Solve a linear equation with the unknown on both sides.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 25.

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Answerx=11x = 113 marks

Worked solution Checked against the mark scheme

Add xx to both sides: 6x−14=526x - 14 = 52

Add 14 to both sides: 6x=666x = 66

x=11x = 11

Watch out: Subtracting x instead of adding it, giving 4x.

Question 26

Sharing in a ratio4 marksGrade 5CalculatorOn both tiers
Use a share in a three-way ratio to find the total, then compare with a new ratio to see how much one person passed to another.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 26.

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Answer£214 marks

Worked solution Checked against the mark scheme

Debbie has 4 parts =120= 120, so 1 part =30= 30 and the total is 9×30=2709 \times 30 = 270.

At first Errol has 2×30=602 \times 30 = 60.

New ratio has 2+5+3=102 + 5 + 3 = 10 parts, so 1 part =27= 27 and Errol now has 3×27=813 \times 27 = 81.

Chris gave Errol 81−60=£2181 - 60 = £21

Watch out: Assuming Debbie still has £120 after the change.

Question 27

Bearings and scale drawings2 marksGrade 4CalculatorOn both tiers
Find a back bearing from a given bearing.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 27.

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Answer327°2 marks

Worked solution Checked against the mark scheme

The return bearing differs by 180°180°.

147+180=327°147 + 180 = 327°

Watch out: Subtracting from 360 to give 213°.

Question 28

Volume and surface area4 marksGrade 5CalculatorOn both tiers
Find the volume of a cylinder, convert it to litres and work out the filling time at a given rate.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 28.

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Answer65 minutes4 marks

Worked solution Checked against the mark scheme

Volume =π×152×43=30 394.9… cm3= \pi \times 15^2 \times 43 = 30\,394.9\ldots\text{ cm}^3

1000 cm3=11000\text{ cm}^3 = 1 litre, so this is 30.3949…30.3949\ldots litres.

Time =30.3949÷0.47=64.67…= 30.3949 \div 0.47 = 64.67\ldots, so 65 minutes

Watch out: Forgetting to convert cm³ to litres.

Question 29

Pythagoras and trigonometry2 marksGrade 5Calculator
Use trigonometry to find a side in a right-angled triangle from an angle and the adjacent side.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 29.

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Answer32.2 cm2 marks

Worked solution Checked against the mark scheme

AB is opposite the 49°49° angle and BC (28 cm) is adjacent, so use tan.

AB=28×tan⁡49°=32.21…AB = 28 \times \tan 49° = 32.21\ldots

So AB=32.2AB = 32.2 cm (3 s.f.)

Watch out: Using sin or cos instead of tan.

Question 30

Simultaneous equations3 marksGrade 5Calculator
Solve a pair of linear simultaneous equations with decimal constants.

© Pearson Education Ltd. November 2023 Paper 2 (Foundation, calculator), question 30.

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Answerx=−2, y=1.5x = -2,\ y = 1.53 marks

Worked solution Checked against the mark scheme

Multiply the first equation by 3: 9x+3y=−13.59x + 3y = -13.5

Subtract the second: 5x=−105x = -10, so x=−2x = -2

Substitute: 3(−2)+y=−4.53(-2) + y = -4.5, so y=1.5y = 1.5

Watch out: Getting the sign wrong when subtracting negative numbers.

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